首项系数

Finally obtains, when besides first item and absolute term, sum of the other coefficient for odd number, this integer polynomial does not have the rational root.

最后得出，除首项和常数项外，当其余各项系数之和为奇数时，该整系数多项式无有理根。

In chapter 3,we investigated the relationship between exponent of convergence to zero - sequence of the solution of certain homogeneous linear differential equation f + Af = 0 and the order of growth of A.

第四部分研究了一类二阶线性微分方程f+Q_1e~(p_1+Q_2e~(p_2)+Q/df=0中p_1，p_2首项系数的比值对方程解的零点收敛指数的影响，并推广到更广泛一类方程。

This test method is called integer-variation test, and it is based on the statistical distribution of the fractional part of a random variable multiplied by an appropriate integer.

证明了首项系数为整数的n个独立随机变量和的小数部分的统计分布性质，并证明了当求和个数趋于无穷时的统计分布性质。

The Mahler measure of a polynomial P is the absolute value of the product of all roots of P that have modulus at least 1 multiplied by the leading coefficient.

中文摘要：多项式的Mahler测度指的是它的所有模大于1的根与其首项系数的乘积的绝对值。

Then we use Cramer\'s rule to obtain an estimate of the degree in q~(1/2) of the leading coefficient of the recurrence.

而后利用Cramer法则得到迭代关系首项系数中q~(1/2)的次数的一个估计。

Firstly, we prove a proposition : the leading coefficient regarded as a polynomial in q~n, q~(1/2 of the recurrence is not equal to zero for all n ≥ [m/2] + 1, where m is the degree in q~(1/2) of the leading coefficient.

首先，我们证明了一个命题：迭代关系的首项系数关于q~n，q~(1/2的多项式对所有的n≥1[m/2]+1均不为零，其中m为首项系数中q~(1/2)的次数。

Depending on the coefficient of the polynomial, we can easily compute the number of modular addition of A mod p by the formulas for any given irreducible monic trinomial and monic pentanomial.

根据该表达式，对任意给定的不可约首一三项式和首一五项式，可以根据该多项式的系数分别得出以广义Mersenne数为模数的取模运算所需要的模加法的次数。

Plunder melds and run with this jewel!

掠夺melds和运行与此宝石！

My dream is to be a crazy growing tree and extend at the edge between the city and the forest.

此刻，也许正是在通往天国的路上，我体验着这白色的晕旋。