边条件

According to the ecological conditions of tropical rain forest in natural protection area and the construction conditions of expressway, the measures of expressway ecological restoration were studied about the slope, median strip, interchange, tunnel and the special areas （large dump, service station, parking lot） in Simao-Xiaomengyang Expressway.

根据云南省西双版纳热带雨林自然保护区生态环境特点和高速公路的建设条件，结合植被的生态恢复与重建理论，分别对思小高速公路的边坡、中央分隔带、立交区、隧道和特殊区域（取弃土场、服务区、停车区等）进行生态景观绿化设计。

By employing the approaches for upper and lower solutions and monotone iterative technique, the authors have obtained the sufficient conditions for the existence of coupled maximal solution and minimal solution.

通过上下解方法和单调迭代技术得到了边值问题存在耦合极大解β-和极小解α-的充分条件。

Two-point boundary value problems of second order mixed type integro-differential-difference equation is studied by means of differential inequality theories.

利用微分不等式技巧研究了某一类二阶混合型积分微分差分方程的两点边值问题，在上下解存在的条件下，得到了解的存在性和唯一性定理。

By use of the stretch and compression fixed point theorem of normic form in cone ,the sufficient conditions for the existence of monotone increasing positive solutions and monotone decreasing negative solutions are obtained to the boundary value problems.

运用锥拉伸与锥压缩不动点定理，分别得到了边值问题单调递增正解和单调递减负解存在的充分条件。

With homogeneous Neumann boundary value condition when the spatial dimension is one. Moreover, some criteria on the global asymptotic stability of the positive equilibrium points for M_

在齐次Neumann边值条件下非负整体解的存在性和一致有界性，并通过构造Lyapunov函数给出M

When the nonlinearity is an odd function, multiple positive solutions for the sec-ond order self-adjoint difference equation with the Neumann boundary conditionΔu(0)= 0,Δu = 0 are obtained by applying Clark's theorem.

另一方面，当非线性项非负且在0~+和+∞是渐近线性的情况下，应用山路引理研究了方程在混合边值条件u(0)= 0，Δu = 0下正解的存在性。

Furthermore, the paper presents a line oriented locating algorithm for fast locating triangles, which has the advantage of unique path and steady operation compared with other locating algorithms.2 Applying the theory of Constraint Delaunay Triangulation, the paper propounds the dynamical algorithm for constructing CDT, which insist that the constraint segments be inserted into the triangulation as soon as possible on the condition that they have been known already.

同时提出了快速定位三角形的直线方向定位算法，该算法与一般方向定位算法相比，具有搜索路径唯一，运行稳健的特点。 2应用约束Delaunay三角网理论，提出了构建CDT的动态算法，提出在约束条件已知的情况下，应尽早嵌入约束边。与传统构建CDT的"两步法"相比，具有速度快，点集可以动态扩充的优点。

All is done in the mapping plane about the developed plane of acylindrical shell.Furthermore,applied orthogonal function expansion technique,the problem can be finally summarized into the solution of a series of infinitealgebraic equations.

在第四章中，在保角映射平面上给出了大开孔圆柱壳在外部载荷作用下，广义内力、边界条件以及孔边应力集中系数的一般表达式。

By use of the average value way and Green formula,oscillation theorems for such equation satisfying two kinds of boundary value conditions is obtained.

考虑一类非线性抛物泛函微分方程的强迫振动性，利用平均值法和格林公式，在两类边值条件下得到这类方程的振动性定理。

Firstly, the three-dimension boundary question and its corresponding variation question concerning the point-source electrical field on a 3-D structure are presented. Secondly, the finite element method is used to solve the variational equation. The study area is divided into many tetrahedral elements. Then, we interpolate with a tri-linear function in each element. So, the variational equation is converted into a linear equation system. Finally, taking into account saving of time, we make use of symmetric successive overrelaxation preconditioned conjugate gradient algorithm to solve large linear system, and obtain the potential value of each node, resulting in the calculation of the apparent resistivity values on the ground surface.

首先给出了三维构造中点源电场的边值问题以及相应的变分问题；然后利用有限单元法求解变分问题，采用四面体单元对研究区域进行剖分，在单元中进行三线性函数插值，将变分方程化为线性代数方程组；最后，考虑到节约计算时间，利用对称超松弛预条件共轭梯度迭代算法求解大型线性方程组，得到了各节点的电位值，进而计算出地表的视电阻率。

Singer Leona Lewis and former Led Zeppelin guitarist Jimmy Page emerged as the bus transformed into a grass-covered carnival float, and the pair combined for a rendition of "Whole Lotta Love".

歌手leona刘易斯和前率领的飞艇的吉他手吉米页出现巴士转化为基层所涵盖的嘉年华花车，和一双合并为一移交&整个lotta爱&。

This is Kate, and that's Erin.

这是凯特，那个是爱朗。