第二点

First, we introduce and discuss the various methods of multivariate polynomial interpolation in the literature. Based on this study, we state multivariate Lagrange interpolation over again from algebraic geometry viewpoint:Given different interpolation nodes A1,A2 .....,An in the affine n-dimensional space Kn, and accordingly function values fi(i = 1,..., m), the question is how to find a polynomial p K[x1, x2,...,xn] satisfying the interpolation conditions:where X=(x1,X2,....,xn). Similarly with univariate problem, we have provedTheorem If the monomial ordering is given, a minimal ordering polynomial satisfying conditions (1) is uniquely exsisted.Such a polynomial can be computed by the Lagrange-Hermite interpolation algorithm introduced in chapter 2. Another statement for Lagrange interpolation problem is:Given monomials 1 ,2 ,.....,m from low degree to high one with respect to the ordering, some arbitrary values fi(i= 1,..., m), find a polynomial p, such thatIf there uniquely exists such an interpolation polynomial p{X, the interpolation problem is called properly posed.

文中首先对现有的多元多项式插值方法作了一个介绍和评述，在此基础上我们从代数几何观点重新讨论了多元Lagrange插值问题：给定n维仿射空间K~n中两两互异的点A_1，A_2，…，A_m，在结点A_i处给定函数值f_i(i=1，…，m)，构造多项式p∈K[X_1，X_2，…，X_n]，满足Lagrange插值条件：p=f_i，i=1，…，m (1)其中X=(X_1，X_2，…，X_n)，与一元情形相似地，本文证明了定理满足插值条件(1)的多项式存在，并且按"序"最低的多项式是唯一的，上述多项式可利用第二章介绍的Lagrange-Hermite插值算法求出，Lagrange插值另一种描述是：按序从低到高给定单项式ω_1，ω_2，…，ω_m，对任意给定的f_1，f_2，…，f_m，构造多项式p，满足插值条件：p=sum from i=1 to m=Ai=f_i，i=1，…，m (2)如果插值多项式p存在且唯一，则称插值问题适定。

Write down so that once a colleague wants me to help him send bill to the client, I took a piece of bill that wrote a number to do not have affix one's seal however only unexpectedly in haste, the client also did not look carefully at that time, later the following day after the client made a telephone call, the work in the same placing's furious resumptive bill, bang ground take the table in me, that appearance, wanted to eat me it seems that, my this all one's life does not forget that his word, he says, bother you sober place is good, you how so stupid, what can you do, do you have a meal is VIP fed?!

记得有一次一个同事要我帮他给客户送发票，匆忙之中我竟拿了一张只填了数字却没有盖章的发票，客户当时也没仔细看，后来第二天客户打了电话之后，同事气冲冲的取回发票，"啪"地一下拍在我的桌子上，那样子，似乎要吃了我，他的那句话我这辈子都忘不了，他说，麻烦你清醒点好不好，你怎么这么笨啊，你会做什么啊，你是不是吃饭都要人喂啊？！

Chapter 4 presents five design criteria of S-boxes of block ciphers, develops a method of constructing large S-box by use of algebraic group operation, proves the balance property of these large S-box, tests the strict avalanche and independence of avalanche variables properties of S-boxes in NEA cipher, analyses the nonlinearity and best linear approximation of the S-box, and finally defines the differential of input/output of S-boxes of this cipher and analyses the distribution of them.

第二部分即第三章，提出了一种新的分组密码类NEA(NEA-4A，NEA-8A，NEA-4B，NEA-8B)，完整地描述了该密码类的加解密过程和密钥协议；证明了NEA-4B和NEA-8B的完全对合性和没有不动点的性质；分析了该密码类的安全特征；具体地介绍了实现该类密码的途径；给出了NEA-4A的计算机C语言程序和样本数据。

During the first night he checked out the situation and at 1am during the second night the all-rounder started his climb.

在第一个晚上，他签出的情况和凌晨1点，在第二天晚上的通才开始了他的攀登。

You will also find the number of skill points available for you to allocate to secondary skills.

你也可以看到还有多少技能点可以分配给第二技能。

Cut a big alphabetic string into a series of alphabetic string section and calculate the character figure of every section of character and accumulation addition to gain (length and accumulation addition) team number of corresponding teams.

该算法是取某个特征字符或特征字符序列做为分割点，把大字符串分割为一系列的字符串段，并计算每一个段的字符数和累加和，得到对组成的数组，这样就把两个大的字符串转换为两个小得多的数组；第二步匹配两个

Cut a big alphabetic string into a series of alphabetic string section and calculate the character figure of every section of character and accumulation addition to gain (length and accumulation addition) team number of corresponding teams. So two big alphabetic strings can be changed into two smaller teams. Second, match two teams (length and accumulation addition) and find matching partners.

该算法是取某个特征字符或特征字符序列做为分割点，把大字符串分割为一系列的字符串段，并计算每一个段的字符数和累加和，得到对组成的数组，这样就把两个大的字符串转换为两个小得多的数组；第二步匹配两个数组，找出匹配项，第三步分别对数组中每一项所对应的字符串片段进行匹配。

Alternating minimization cost function and maximization poster probability is proposed to restore the blurred image. The method is divided two step, one step is EM step, it is to estimate the PSF by using minimimum-error criteria, the other step is M step, we use MAP criteria to restore the blurred image.

EMM方法分为两个步骤，第一个步骤是EM步骤，利用最小恢复残差准则，估计系统的点扩散函数PSF，第二个步骤是M步骤，利用最大后验概率准则恢复模糊图像。

It points out the topic, meaning and creative; introducing the consist and principle of the intelligent vehicle navigate system in chapter 2; analyzing the method of GPS-oriented and the error origin in chapter 3; analyzing briefly the principle and merged method of interspaced diversity and resist multi-decline in chapter 4; introducing the hardware and software realization of ambulant station of intelligent vehicle navigate /dispatcher system based on multi-GPS antenna in detail in chapter 5; giving the debugging and simple trial result of ambulant station in chapter 6; The lasted propose solving tactics to problem that exist in studying, draws a conclusion of this thesis and plans the future researching works.

指出本课题的研究的主题、意义及创新点；第二章概括性介绍了智能车辆定位导航系统的组成与原理；第三章分析了GPS定位的方法和误差来源；第四章重点分析了空间分集抗多经衰落的原理和信号合并方法；第五章详细介绍了多GPS天线智能车辆导航/调度系统车载台的软硬件实现；第六章给出了车载台的调试和简单试验结果。最后对研究中存在的问题提出了解决策略及下一步的研究方向。

I had made a great number of Dongmanmi this, and they think you love is like animated cartoon.

第二就是要经常自己动手做点跟动漫相关的物品，也是非常有好处的。

And Pharaoh spoke to Joseph, saying, Your father and your brothers have come to you.

47：5 法老对约瑟说，你父亲和你弟兄们到你这里来了。

Additionally, the approximate flattening of surface strip using lines linking midpoints on perpendicular lines between geodesic curves and the unconditional extreme value method are discussed.

提出了用测地线方程、曲面上两点间短程线来计算膜结构曲面测地线的方法，同时，采用测地线间垂线的中点连线和用无约束极值法进行空间条状曲面近似展开的分析。