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The program for the approximate value,using linear interpolation method and qua...

分别用线性插值和二次插值求数的近似值的程序!

The algorithm is implemented by Fourier transform to obtain the real part and imaginary part of voltage based on digital sampling; and by trigonometric function to gain the sine or cosine dynamically; and then by Taylor series binomial of arc sine function to acquire the actual angle.

通过对数字化采样进行傅立叶变换获得电压的实部和虚部,动态地求取相位角的正弦值或余弦值,然后采用其反函数的泰勒级数二项式得到相位角度。

In Chapter 1, two solutions to the elliptical boundary value problem have been constructed through a monotone iterative process, and they might be identical. In Chapter 2, the author expresses the local solution to the parabolic initial boundary value problem taking advantage of Green function. In Chapter 3, the asymptotic solution to the initial value problem of Duffing equation is obtained and the method for finding the approximate solution to the inverse problem is put forward.This paper is planned with a view to the author's research means.

从研究结果看:第一章通过单调迭代过程构造出椭圆型方程的边值问题的两个解,并且指出二者可能是同一个解;第二章利用格林函数给出了抛物型方程的初边值问题的局部解的解析表达式;第三章中,先对Duffing方程的初值问题写出解的渐近展开式,再对其反问题提出一种求近似解的方法。

These curves contain a shape parameter which can adjust the softness of curve and have the same continuity with the original B-spline. In succession, using the positive conditions of Bernstein polynomial to find a range in which the shape parameter takes its value so as to make the corresponding interpolating curves monotonicity-preserving and C~2 continuous.

利用奇异混合的思想构造出一类带有形状参数的多项式样条曲线,即均匀α-B样条曲线,在无需反求方程组、迭代过程和最值求解的情况下就能轻松做到插值给定的点列;它含有形状参数α,这就增加了曲线的柔性,同时又和原B样条曲线具有相同的参数连续性。

According to the characteristics of the gray projection curves, a pair of maximum and minimum points are found near the central position of each gray projection curve. The differences in position are calculated respectively and the scale change parameter is obtained as the ratio of both differences.

此时,可根据尺度变化下图像灰度累积投影曲线的特点,分别计算参考帧和当前帧的投影曲线上一对极大—极小值点的坐标差值,以它们的比值作为缩放系数,实现实时求取。

First, the relative curvature of a certain curve at its first end and the directional angle of the first port tangent vector of that curve as well as the weight factor of the interpolation curve are given, then all the other control vertexes can be gotten by using the conditions of G continuity, and a method to construct transitional curves is also introduced so that we can get the closed interpolation curve which achieves G continuity globally.

首先给定某段曲线的首端相对曲率和该段曲线的首端切矢量的方向角以及插值曲线的权因子,然后利用G2连续条件求出其余控制顶点,并给出了构造过渡曲线的方法,得到了G2连续的闭插值曲线。

According to the frequency-domain convolution theorem, we can prove the peak frequency and phase are frequency and phase of the harmonic wave signal.

根据频域卷积定理证明最大峰值点的频率和相位就是信号的实际频率和相位,依据由卷积关系得出的关于幅值的方程求出校正幅值。

The main purpose is to construct cubature formulae on an arbitrary spherical triangle. Firstly a method for accurately computing the definite integral of spherical polynomial functions on a spherical triangle is proposed.

本文主要研究定义在球面三角形上函数的数值积分,通过积分的插值多项式函数构造具有多项式精度的插值型求积公式,以及给出精确计算球面三角形上多项式函数方法。

A method of construct a quadratic uniform B-spline curve through data points is given.If the relative curvature of a certain curve on the first control point and the direction angle of the first port's tangent vector is given,here can get the whole curve by using the character of the port of quadratic uniform B-spline curve.

提出了一种二次均匀B样条插值曲线的构造方法,首先给定某一段曲线首点的相对曲率和该段曲线的首端切矢量的方向角,利用二次均匀B样条曲线的端点性质,求出其余各段曲线控制顶点,来生成整条插值曲线。

If the measurement data are demarcated, the acceleration curve can also be calculated by solving the second order differential coefficient of measurement curve.

如果对测量值进行标定,还可以通过对测量值曲线求二次导数得到振源的加速度曲线。

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推荐网络例句

The reasons of iron ions content overproof in grade Ⅱ desalting water system,such as variation water quality,contamination of regenerant , operation adjustment of pretreatment system and switching operation of bed were discussed.

对二级脱盐水系统中铁离子含量超标的原因,如来水水质发生波动、再生剂受到污染、预处理系统操作调整、床体运行切换等进行了论述。

You were hired to drum up new business, so go and do it.

公司雇你招徕新业务,你就做你的事好了。

Who is in possession of this?

这是谁的?