格林

National Bureau of Economic Research and a Nonresident Senior Fellow at Brookings.

格林斯通是麻省理工学院经济系环境3M 经济学讲座教授，也是国家经济研究局

A town of northwest Massachusetts north of Northampton. The first cutlery factory in America was established here in the early1800's.

格林菲尔德美国马萨诸塞州西北的一个城镇，位于北安普敦的北部。19世纪早期，美国的第一家刀剪业工厂建立于这里。

A form of solitaire.A town of northwest Massachusetts north of Northampton. The first cutlery factory in America was established here in the early1800's.

格林菲尔德美国马萨诸塞州西北的一个城镇，位于北安普敦的北部。19世纪早期，美国的第一家刀剪业工厂建立于这里。

The closed-form expressions are derived so that all required differentiations are obtained in closed form and numerical differentiation can be avoided.

特别是对微带和缝隙混合结构的空域MoM分析，旋度算子的微分在谱域进行，并可以给出它们的解析表达式，其对应的空域格林函数可通过高阶的Sommerfeld恒等式获得，从而避免了数值微分。

In this article the Green function theory, numerical methods for carrying out the self-energy calculations, simplified schemes, and applications to various systems are described.

在本文中，格林函数理论，数值方法，简化格式及其在各种系统中的应用将一一描述。

Profs Eichengreen and O'Rourke describe this contrast.

埃森格林和欧罗克教授描述了两者的差别。

This obit photo needs to get to layout ASAP

格林从他位于房间远处角落办公桌叫道："这儿需要ASAO布局轨道图片。"

Also on the team are Emily Prentiss,the daughter of high-powered diplomats who recently joined the team and must prove her worth to Hotchner;Special Agent Derek Morgan,an expert on obsessional crimes;Special Agent Dr.

专家小组的成员还包括对性犯罪有很深研究的特工艾尔·格林威；强迫性犯罪方面的专家德瑞克·摩根；智商超高但社会交往能力极低的天才博士斯宾塞·瑞德。

On Sunday afternoon, he does his homework.

王叔叔是格林先生的一个好朋友。

The distribution of the interference fringes and its change with respect to the change of optical path difference are analysed and some of its applications are also introduced.

本文介绍了泰曼-格林干涉仪的一种变形，分析了在这种情况下所获得的干涉条纹的分布，及其随光程差变化而变化的规律，并介绍了它的应用。

Singer Leona Lewis and former Led Zeppelin guitarist Jimmy Page emerged as the bus transformed into a grass-covered carnival float, and the pair combined for a rendition of "Whole Lotta Love".

歌手leona刘易斯和前率领的飞艇的吉他手吉米页出现巴士转化为基层所涵盖的嘉年华花车，和一双合并为一移交&整个lotta爱&。

This is Kate, and that's Erin.

这是凯特，那个是爱朗。