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First, a maximal deadly siphon can be obtained by using the mixed integer programming technique, and a monitor is added to a minimal siphon that needs to be controlled, which is derived from the maximal deadly siphon in order to ensure the controllability of all siphons of Petri nets.

首先对Petri网模型运用混合整数规划算法求取一个最大的死信标,然后从最大的死信标中求取一个需要受控的极小信标,并对其添加控制库所,从而保证所有信标的最大可控。

Consider the problem 1|s_, outtree |∑w_jC_j , we use the method of the maximal family tree to sol...

最后把NP-难的问题P_m|s_|∑w_jC_j转化为整数规划模型,并设计了LMP的列生成算法,结合Dantzig-Wolfe分解技术,利用动态规划对其进行求解。

The problem of maximum security route in transportation is discussed in this paper.

讨论了最安全路线运输问题,给出了该问题的混合整数规划模型,并提出了该问题的解法,最后给出了一个实例

Because of the distinct difference in the background color, we use a binary algorithm based on gray mean value and a two-step segmentation method to segment the image. In order to reduce the influence of unlinear change on the image, we divide the shooting score into two parts: integral and floating.

针对靶图像背景颜色对比度大的特点,采用一种基于灰度期望值的图像二值化算法,通过逐步分离的方法,将靶环从背景中分割出来;针对影响靶数精度的主要因素,将靶数分解为整数与小数两部分。

This invention provides compounds of Formula; wherein: R is a moiety selected from the group: and n is an integer of 1 or 2; R is selected from hydrogen, amino,-NRR, alkyl of 1 to 12 carbon atoms optionally substituted, aryl of 6, 10 or 14 carbon atoms optionally substituted, alkenyl of 2 to 12 carbon atoms optionally substituted, alkynyl of 2 to 12 carbon atoms optionally substituted, halogen, and a 5 to 10 membered heteroaryl ring optionally substituted, having 1 to 4 heteroatoms independently selected from N, O and S; R is selected from hydrogen, alkyl of 1 to 12 carbon atoms optionally substituted, aryl of 6, 10 or 14 carbon atoms optionally substituted, alkenyl of 2 to 12 carbon atoms optionally substituted, vinyl, alkynyl of 2 to 12 carbon atoms optionally substituted and halogen; R is H, alkyl of 1 to 12 carbon atoms optionally substituted, cycloalkyl of 3 to 8 carbon atoms, bicycloalkyl of 5 to 10 carbon atoms or aralkyl optionally substituted; R is OH or -OH; R and R are each independently H or alkyl of 1 to 12 carbon atoms or when optionally taken together with the nitrogen atom to which each is attached form a 3 to 8 membered saturated heterocyclyl ring; R is alkyl of 1 to 12 carbon atoms optionally substituted; or a tautomer or pharmaceutically acceptable salts thereof.

本发明提供式的化合物;其中:R 1 为选自基团和的部分;n为整数1或2;R 2 选自氢、氨基、-NR 6 R 7 、具有1到12个碳原子的视情况经取代的烷基、具有6个、10个或14个碳原子的视情况经取代的芳基、具有2到12个碳原子的视情况经取代的烯基、具有2到12个碳原子的视情况经取代的炔基、卤素和具有1到4个独立地选自N、O和S的杂原子的视情况经取代的5元到10元杂芳基环;R 3 选自氢、具有1到12个碳原子的视情况经取代的烷基、具有6个、10个或14个碳原子的视情况经取代的芳基、具有2到12个碳原子的视情况经取代的烯基、乙烯基、具有2到12个碳原子的视情况经取代的炔基和卤素;R 4 为H、具有1到12个碳原子的视情况经取代的烷基、具有3到8个碳原子的环烷基、具有5到10个碳原子的双环烷基或视情况经取代的芳烷基;R 5 为OH或-OH 8 ;R 6 和R 7 各自独立地为H或具有1到12个碳原子的烷基,或当视情况与其所连接的氮原子连接在一起时形成3元到8元饱和杂环基环;R 8 为具有1到12个碳原子的视情况经取代的烷基;或其互变异构体或医药学上可接受的盐。

Let〓be a meromorphic function of finite order and〓z,where qis rational and pis a polynomial.Then every cycle of Bakerdomains of f contains a singularity of〓.

推论3.4设q是一个有理函数,p是一个多项式,m,n是满足〓的两个正整数,又设f是一个满足如下微分方程的亚纯函数〓(3.2)则f的每一个Baker域循环一定含有〓的奇异点。

Finishing in 3rd Place in the Men's Division was Gary Neal of Spartanburg, SC In 4th Place was Rusty Jackson III of Allensville, Ky. Tying for 5th Place in the Men's Division is Brian Belobradic of Whitby, Ontario, Canada and Eddie Little of Salisbury, NC Defending champion Michell Monk of Palm Bay, Fla. rounded out the top finishers in the Women's Division with a 3rd Place finish.

整理在第三位,在男性的分工是加里奥尼尔的斯帕坦堡,资深大律师在第四位,是生锈的杰克逊的第三艾伦斯维尔,肯塔基州并列第五位,在男性的分工是布赖恩belobradic的惠特, Ontario ,加拿大和埃迪小梳士巴利,数控卫冕冠军michell和尚棕榈湾,佛罗里达州的整数列顶端的优质买家询盘,在妇女的分工与第三的成绩。

Then a filled function method for the integer programming problem is proposed,which tries to find a better discrete local minimal solution of the problem by minimizing a filled function.

该方法通过寻找填充函数的离散局部极小解以期找到整数规划问题的比当前离散局部极小解好的解。该文的算法是直接法,数值试验表明算法是有效的。

The problem given in (6),(7),(8) and (9) is a non-linear minimization problem with integer variables.

问题给出了( 6 ),( 7 ),( 8 )及( 9 )是一个非线性极小化问题与整数变数。

If the integer is negative, the character representation is prefixed by a minus sign.

如果该整数是负值,那么将使用减号作为前缀。

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