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The first method is similar as [8] except we choose the Hermite Normal Form decomposition instead of Smith Normal Form; the second one takes the idea of integer reversible mapping [9], [10]. If the approximately cubic shaping is used, both techniques would lead to an asymptotical PAR value equalto 3 when SNR is large.

第一种方法利用Hermite Normal Form分解来达成,第二种方法则是利用可逆整数对应来完成,在时空编码个数足够大时,二者皆可渐近的降低峰均比到3

Because of the complexity of the problem, three heuristics are proposed to solve the problem modelled by linear integer programming.

由于该问题的规模较大,本文提出了三种启发式算法用以求解已提出的线性整数规划模型。

The integer, 3, will be the first number in the hexadecimal formula.

整数, 3 ,将第一个数字的十六进制的公式。

Theorem 2.4.2 Let F be a family of holomorphic functions in a domain D and k≥2 be a positive integer, K be a positive number and letα be a polynomial of degree p.

定理2.4.2设F为区域D内的一个全纯函数族,k (≥2)是一正整数,α是一次数为p≥1的多项式。

"Home-brew".The most complicated repeated qualifier is {m,n}, where m and n are

最复杂的重复限定符是{m,n},其中 m 和 n 是十进制整数

In this paper, the following statements were proved: is chaintransitive if and only if is chaintransitive; if a homeomorphism is a Lipschitz map, then has the average shadowing property if and only if has the average shadowing property.

设是紧致度量空间,:X→X是连续的,n为任一给定的正整数,证明了:是链可迁的当且仅当是链可迁的;若同胚是Lipschitz映射,则有平均跟踪性当且仅当有平均跟踪性。

In order to improve the computational efficiency, a branch algorithm for general integer linear programming problems on the objective function hyperplane shifts was presented.

为了提高求解一般整数线性规划问题的效率,提出了一种基于目标函数超平面移动的分支算法。

A necessary and sufficient condition is proved here for judging whetherthe ideal class group Hof a quadratic function field 〓has a cyclicsubgroup of order n for any given n.

给出了一般二次函数域的理想类群含有n阶循环子群的充分必要条件(其中〓是任意事先给定的正整数)。

Let be a sequence of independent and identically distributed random variables,and ,exist ,then,for any value ,.

Corollary 4.1 设相互独立的随机变量有相同的分布,且,存在,则对于任意正整数,有。

The ' is ' operator compares the identity of two objects; the id function returns an integer representing its identity (currently implemented as its address).

is ' 操作符可以比较两个对象的标识; id 函数会返回对象标识的一个整数表示。

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