嵌套的

The update operation is a bit tricky because the properties mapping between the passed entity and the entity from the database is done dynamically, so any nested object will not be mapped.

更新操作有点棘手，因为两者之间传递的实体和从数据库实体属性映射完成动态，所以任何嵌套的对象将不会被映射。

Third state, nested, which is a characteristic of the long-running state. Nested conversations

其实还有一种嵌套的，是长期运行的一种特性。

The program edited by LISP Language,which is embeded in AutoCAD,can complish the design for ensilage dump conveyor belt.

使用AutoCAD嵌套的LISP语言编写程序来完成强力胶带输送机辅助设计。

In this dissertation, we construct the Bariev model with nine kinds of boundary fields by the matrices K_± defining the boundaries. And then the Lax operator is given in the form ofmatrix, as well as the basic quantities, e.g., the R -matrix, the monodromy matrices and the transfer matrices are defined. By using the expression of the local Lax operator of the model,the action of the monodromy matrices T, T~(-1), U_ on the pseudo-vacuum state is given outin detail. Furthermore, the main fundamental commutation relations are obtained through the reflection equations, the recursive n-particle state as well as the one-particle exact solution is given and the Bethe ansatz equations are found accordingly. Finally, we list the nesting boundary K matrices, which play a crucial role for obtaining the n-particle solution and finding the Bethe ansatz equations, the eigenvalues of the transfer matrices and the energy spectrum of the system by means of the nested algebraic Bethe ansatz method.

在这篇文章中，我们利用边界K_±矩阵构造出了具有九种边界场的Bariev模型，同时给出了该模型L算子的具体矩阵表示形式，并定义了R矩阵，monodromy矩阵以及转移矩阵；接着利用L算子的矩阵形式，给出了其对应monodromy矩阵T、逆矩阵T~(-1)作用到真空态上的值，并利用Yang-Baxter关系及反射方程得到了双行monodromy矩阵U作用到真空态上的值；然后利用反射方程通过复杂的计算得到了一系列重要的基本对易关系式，并给出了模型的递推的多粒子波函数、单粒子解及Bethe ansat方程；最后给出了模型的嵌套的边界K矩阵的具体形式，从而为运用嵌套Bethe ansatz方法求解该模型的多粒子解、Bethe ansatz方程以及系统的能谱打下了很好的基础。

Less relevant for implementing actual procedure calls. When a nesting level is

中。为了实现嵌套，代码在使用ENTER指令时必须指明当前嵌套的层数

By analyzing the YAWL,it can be found that the enabling of a OR-join task which has another OR-join in its branch will be in advance.

为避免YAWL建模过程中嵌套使用或汇合任务可能出现的提前使能问题，提出了使用异或汇合和与汇合任务将嵌套的或汇合任务进行替换的方法，通过替换有效解决了这一问题，而且结合Reset网，对改进作形式化说明。

With this, it's three spheres, one inside the other...

而这个，它是三个互相嵌套的球体。。。

With this, its three spheres, one inside the other...

而这个，它是三个互相嵌套的球体。。。

By utilizing three benezenemulticarboxylate derivatives (H2chdc, H2aip, NaH2sip), we obtain 12 coordination polymers. Especially, compelexes 1 and 2 are based on one-dimensional ···OHInOHIn···chains as building units, while complex 3 is based on double four-ring [In8(μ2-O)4(μ2-H2O)8]16+, complex 4 is based on trinuclear In3(μ3-O)(CO2)6, complexes 11 and 12 are both based on nested bistranded helices.

选择了三类取代苯羧酸配体： 2，5-二羟基-1，4-对苯二甲酸(2，5-H2chdc)； 5-氨基间苯二甲酸(5-H2aip)； 5-磺酸基间苯二甲酸钠盐(5-NaH2sip)和InCl3反应合成了十二个配位化合物：其中1、2以···OHInOHIn···链为构筑单元， 3以双四元环[In8(μ2-O)4(μ2-H2O)8]16+为构筑单元，4以棱柱状三核铟In3(μ3-O)(CO2)6为构筑单元，而11、12以嵌套的双股螺旋链为构筑单元。

That's not too hard, if we add the restriction that we only allow unnested pairs of parentheses in URLs.

如果限制在URL只使用不嵌套的括号的话，那么该问题不难解决。

With Death guitarist Schuldiner adopting vocal duties, the band made a major impact on the scene.

随着死亡的吉他手Schuldiner接受主唱的职务，乐队在现实中树立了重要的影响。

But he could still end up breakfasting on Swiss-government issue muesli because all six are accused of nicking around 45 million pounds they should have paid to FIFA.

不过他最后仍有可能沦为瑞士政府&议事餐桌&上的一道早餐，因为这所有六个人都被指控把本应支付给国际足联的大约4500万英镑骗了个精光。