对称面

One is concave whereas the other is convex and faces the longitudinal plane of symmetry X.

一个是凹入的，而另一个是凸起的，并面向纵向对称面X。

"F" is the distance between point P' and the tangent to the concave area in the maximum point of concavity measured in projection view on the plane of symmetry Y.

"f"为在对称面Y上的投影视图上测量的点P'和最大凹状点上的对凹入区域的切线之间的距离。

Height datum: Symmetry plane or the bottom surface.

高度基准上下对称面或底平面(Z = 0)。

Length datum: Symmetry plane or the end surface.

长度基准左右对称面或左端面

A half of a symmetrical, approximately spherical object as divided by a plane of symmetry.

半球体：一个对称的、近似球体的物体的一半，如被对称面分开者

Preformed malleable dental crowns with a side-generic external shape with a plane of symmetry in the facial-lingual direction and/or a plane of symmetry in the mesial-distal direction.

具有在颊舌方向上的对称面和/或近远中方向上的对称面的侧面通用外形的预制的可煅的牙冠。

On the rhombohedron face {1011}, Dauphine twinning showed different shapes of etching pits between individuals, because rhombohedron positive form {1011} and negative form {0111} appeared on both sides of twin partition line, while Brazil twinning showed symmetry plane between the irregular triangle etching pits of individuals. On the trigonal prism section 11(average20, Dauphine twinning showed different shapes of etching pits between individuals, because trigonal prism positive form {1120} and negative form {2110} appeared on both sides of twin partition line, while Brazil twinning should show symmetry plane between the ellipse or quadrilateral etching pits of individuals, which was not observed.

菱面体{1010}面上存在道芬双晶处，道芬双晶双晶缝合线两端分别是菱面体正形、菱面体负形出露处，导致蚀坑形状不同；菱面体{1011}面上存在巴西双晶处，不规则三角形蚀坑形态的方位关系为对称面关系；三方柱切面{1120}面上存在道芬双晶处，道芬双晶双晶缝合线两端分别是三方柱正形、三方柱负形出露处，导致蚀坑形状不同；三方柱切面{1120}面上存在巴西双晶处，椭圆形或四边形蚀坑方位应为对称面关系，但实验中未见到。

3 Axially Symmetric Problems for Space Among spatial problems, if the elasticity body's geometric shape,restraint condition and any external factors are symmetrical in a certain axis(any plane which passes this axis is all symmetrical one),then all stresses,deformations and displacements are symmetrical in this axis.

§8-3 空间轴对称问题在空间问题中，若弹性体的几何形状，约束情况以及所受的外来因素，都对称于某一轴(通过这个轴的任一平面都是对称面)，则所有的应力，形变和位移也对称于这一轴。

得 (1 2r ) A 1 + A2 = 0 由条件得 4π(1 )A1 + 2A2 = P P (1 2) A1 =, A2 = P 2π 2π由及二式的联立求解,得 42 Substitute the obtained A1 and A2 into the forgoing representations, we get (1 +)P rz (1 2)r ur = R2 R + z 2πER (1 +)P z2 ω= 2(1 )+ 2 2πER R P (1 2)R 3r 2 z σr = 3 2 2πR R + z R (1 2)P z R σθ= 2 R R + z 2πR 3Pz3 3Pr z 2 σ z = 5 ,τ zr =τ rz = 2πR 2πR5 43 将得出的A1及A2回代,得(1 +)P rz (1 2)r ur = R2 R + z 2πER (1 +)P z2 ω= 2(1 )+ 2 2πER R P (1 2)R 3r 2 z σr = 3 2 2πR R + z R (1 2)P z R σθ= 2 R R + z 2πR 3Pz3 3Pr z 2 σ z = 5 ,τ zr =τ rz = 2πR 2πR5 44 §8-4 Spherically Symmetric Problem For Space Among spatial problems, if the elasticity body's geometric shape,restraint condition and any external factors are symmetrical in a certain point (any plane which passes this point is all symmetrical one),then all stresses,strains and displacements are symmetrical in this point.

§8-4 空间球对称问题在空间问题中，如果弹性体的几何形状，约束情况以及所受的外来因素，都对称于某一点(通过这一点的任意平面都是对称面)，则所有的应力，形变和位移也对称于这一点。这种问题称为空间球对称问题。

The knock-down of the three LjCYC genes gives rise to the ventralized identity to all petals, which are keeled shape, resulting in a floral transformation from a zygomorphy to an asymmetry, indicating that the asymmetry floral pattern could be a ground stage before LjCYC1, LjCYC2 and LjCYC3 being recruited in the control of floral asymmetrical development in Lotus japonicus.

本实验得到了LjCYC1、LjCYC2和LjCYC3表达均下调的转基因株系L1+2Ri/kew1，该植株所有花瓣呈现腹部属性，出现了花瓣形态全是龙骨瓣状的非对称花瓣，花型也从两侧对称转化为无对称面；这种花型表明，在LjCYC1、LjCYC2和LjCYC3等三个基因全失活的情况下，龙骨瓣状花瓣应该是一个基准状态。

In the negative and interrogative forms, of course, this is identical to the non-emphatic forms.

。但是，在否定句或疑问句里，这种带有"do"的方法表达的效果却没有什么强调的意思。

Go down on one's knees;kneel down

屈膝跪下。。。下跪祈祷