寄存器
- 与 寄存器 相关的网络例句 [注:此内容来源于网络,仅供参考]
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The nonobvious relation is between the register state R of the original program and the location state R′ of the transformed program. Given that each pseudo-register r is mapped to the location j, we could naively require that R = R′j(r for all r.
原始程序的寄存器状态R和变换后程序的存储状态R′之间的关系并不那么明显,假定每个伪寄存器r映射到分配单元j,我们可以简单地要求对所有r有R = R′j
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Remember that the libcwrapper function stashed the system call number in register%eax. When we are in the 64-bit kernel,%eax is thelower32-bits of register %rax
注:22.libc的包装函数是用寄存器eax来存放调用号,Opteron中rax寄存器的低32位就是eax,因此这里直接察看其内容,转换成10进制数格式。
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Remember that the libc wrapper function stashed the system call number in register %eax. When we are in the 64-bit kernel,%eax is the lower 32-bits of register %rax
注: 22。 libc的包装函数是用寄存器eax来存放调用号,Opteron中rax寄存器的低32位就是eax,因此这里直接察看其内容,转换成10进制数格式。
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The compiler generates prolog and epilog code to save and restore the ESI, EDI, EBX, and EBP registers, if they are used in the function.
在ESI、EDI、EBX和EBP寄存器当中,如果她们在程序中被使用到的话,编译器会生成序言和结语代码来存储和恢复这些被使用的寄存器的内容。
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In Direct3D 10, adjacent stages effectively share a register array, where the upstream stage writes data to specific locations in the register array and the downstream stage must read from the same locations.
在D3D10中,邻接的流水线阶段可以有效的分享寄存器数组,前一个阶段把数据写入寄存器数组特定的位置,后一阶段从相同的位置读取。
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That also means you don't have to play with segment registers. you can use any segment register to address any point in the memory space. that's a great help to programmers. this is what makes win32 assembly programming as easy as c.
这同时也意味着您无须和段寄存器打交道,您可以用任意的段寄存器寻址任意的地址空间,这对于程序员来说是非常方便的,这也使得用32位汇编语言和用c语言一样方便。
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That also means you dont have to play with segment registers. You can use any segment register to address any point in the memory space. Thats a GREAT help to programmers. This is what makes Win32 assembly programming as easy as C.
这同时也意味着您无须和段寄存器打交道,您可以用任意的段寄存器寻址任意的地址空间,这对于程序员来说是非常方便的,这也使得用32位汇编语言和用C语言一样方便。
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That also means you don''''t have to play with segment registers. You can use any segment register to address any point in the memory space. That''''s a GREAT help to programmers. This is what makes Win32 assembly programming as easy as C.When you program under Win32, you must know some important rules.
这同时也意味着您无须和段寄存器打交道,您可以用任意的段寄存器寻址任意的地址空间,这对于程序员来说是非常方便的,这也使得用32位汇编语言和用C语言一样方便。
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SHIFT_8REG is eight with a displacement of the functional Register, Each will enter the data from the register into the lowest point, and the left shift accordingly.
详细说明: SHIFT_8REG是8位的一个具有移位功能的寄存器,每一次数据打入都会从这个寄存器的最低位打入,并相应进行向左移位。
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After an interrupt is generated, the CPU compares the interrupt number (x8) against the size of the IDT -- stored in the interrupt descriptor cache register. If the INT# x 8 doesn't exceed the IDT size, then the interrupt is considered invokable, and the IDT base address is fetched from the descriptor cache; then the ISR's protected mode address is fetched from the IDT.
在产生一个中断之后, CPU 将会把中断号(乘以8)和 IDT 的长度进行比较( IDT 的长度存储在中断描述符缓冲寄存器中),如果中断号乘以8之后的值没有超过 IDT 的长度,则该中断被认为是可调用的,然后将 IDT 的基址从中断描述符缓冲寄存器中取出; ISR 的保护模式帝制从 IDT 中取出。
- 推荐网络例句
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With Death guitarist Schuldiner adopting vocal duties, the band made a major impact on the scene.
随着死亡的吉他手Schuldiner接受主唱的职务,乐队在现实中树立了重要的影响。
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But he could still end up breakfasting on Swiss-government issue muesli because all six are accused of nicking around 45 million pounds they should have paid to FIFA.
不过他最后仍有可能沦为瑞士政府&议事餐桌&上的一道早餐,因为这所有六个人都被指控把本应支付给国际足联的大约4500万英镑骗了个精光。
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Closes the eye, the deep breathing, all no longer are the dreams as if......
关闭眼睛,深呼吸,一切不再是梦想,犹如。。。。。。