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奇数

与 奇数 相关的网络例句 [注:此内容来源于网络,仅供参考]

Finally obtains, when besides first item and absolute term, sum of the other coefficient for odd number, this integer polynomial does not have the rational root.

最后得出,除首项和常数项外,当其余各项系数之和为奇数时,该整系数多项式无有理根。

In additive prime number theory,a classical result of Hua states that,every suffi-ciently large odd number N can be represented as 〓,where 〓 is aninteger and 〓 are primes,which can be regarded as an extension of Goldbach-Vinogradov Theorem.

堆垒素数论中一个经典的结果是华罗庚教授证明的:任一个充分大的奇数N都可以表为N=〓+〓+〓,其中λ是一正整数,p1,p2,p3是素数,这一结果可以看作著名的Goldbach-Vinogradov定理的推广。

Carries on the classification to the question, analyzes each kinds of questions the explanation mentality, inquires and summarizes that it can 100 within the odd number aliquot aliquot characteristic, finally discovered that any integer can by the lowliest place digit be 1,3,7,9 aliquot integer characteristics according to the lowliest place numeric classification, each kind has certain rule.

对问题进行分类,分析各类问题的解答思路,探寻、总结出能被100以内奇数整除的整除特征,结果发现任何一个整数能被末位数字是1,3,7,9整除的整数特征可按末位数字分类,每一类都有一定的规律。

Arithmetic progression: starting from the second, an increase each by the former posed a constant sequence, such as the odd-numbered 1,3,5,7 ... geometric progression: from the second onwards, each of which is th power of the number of previous ...

算术级数:从第二项起,每一项均由前一项加一个常数所构成的序列,如奇数1,3,5,7…几何级数:从第二项起,每一项是前一项的多少次方。。。

Since the problem of GVT with two primes restricted in arithmetic progressionsof the same moduli k is actually the same as the previous problem(2),we consideredthe problem of GVT with exactly one prime in an arithmetic progression.

两个素数取值于相同模的算术级数中的GVT问题实际上和前面的的问题(2)是一样的,于是只需考虑一个素变数在算术级数中取值的奇数Goldbach问题。

Generally, The gauge reading demarcated in the laboratory is increasing arithmetic progression,so we can use null method that we intercalate sequential numbers in order to calculate simply. The sum of these sequential numbers are zero. We must intercalate different sequential numbers while the number of trials is odd or even.

因为在试验室标定时,压力表读数一般是按照等差数列递增的,所以为了计算的简便,可用"零点法"设置等差序号,使这一列数据的总和为零,此时要注意当试验次数分别为偶数和奇数时不同地设置等差序号的方法。

Baud rate 1200, 2400, 4800, 9600 or 19,200 programmable Parity Even, odd or no parity.

波特率1200 , 2400 , 4800 , 9600或19200可编程奇偶即使,奇数或没有均等。

Code of drawing a map in Bessel Newmann function, WINDOWSthe generalized Bessel equation and the Hankel function.

并利用球Bessel函数与半奇数阶Bessel函数的关系计算了本征函数的模方。

For example, books usually have chapters set to always start on an odd-numbered page.

例如在书籍中每一章的第一页通常在奇数页, OOo 将在两个奇数页见插入空白页。

In Africa, most countries with the view that odd color negative; while in Japan, while odd-numbered side of the coin is to see Fuxing auspicious figures, not even of interest on.

在非洲、大多数国家认为奇数带有消极色彩;而在日本,奇数则被看面是吉祥福星的数字,对偶数却不感兴趣。

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此刻阴唇已经几乎完全的缝在一起了,排除多余淤血体液的管子和Foley导管从顶端冒出来。

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