反对数
- 与 反对数 相关的网络例句 [注:此内容来源于网络,仅供参考]
-
Transforming functions are similar to logarithm, sigmoid, arctangent, etc, not depended on a prior knowledge of characteristic exponent, and facilitative for practice application.
变换函数可以是对数型、Sigmoid型、反正切型等,这些变换函数不依赖于对特征指数α的先验知识的了解或估计,便于工程应用。
-
When seismic wavelet is in non-minimum phase , we can make it have smaller phase by doing exponential weighting . As for nonwhite noise problem of reflection coefficient , we may employ logarithmic power spectrum to estimate the autocorrelation function of seismic wavelet , then obtain seismic wavelet and deconvolution opera .
当地震子波为非最小相位时,可利用指数加权方法使之小相位化;对于反射系数非白噪声问题,本文提出利用对数功率谱来估算地震子波的自相关函数进而求取地震子波以及反褶积算子的方法;对于理想的期望子波,本文采用"宽带雷克子波"作为期望输出子波。
-
The model is adopted to produce the inverse time overcurrent characteristic curves. In order to solve the problem of the inverse-time characteristic curve of exponential calculation into a microprocessor capable, this paper discusses it and puts forward solutions. The simulation shows it can be used in the actual application of microproc...
根据该模型得到的过流保护反时限动作特性曲线,为了解决反时限特性曲线中的对数运算转换为微处理器能够处理的运算的问题,对其进行了探讨,并提出了解决方法,通过仿真表明完全可以在实际的微机保护装置中应用,具有较高的实际应用价值。
-
The most important exponential function is ex, the inverse of the natural logarithmic function.
最重要的指数函数是ex,即自然对数函数的反数
-
The first of these integrals is seen to be a logarithmic form and the second the inverse tangent form.
这些积分中的第一个被看成是对数形式,而第二个被看成是反正切形式。
-
The most important ex ponential function is ex , the inverse of the natural logarithmic function.
最重要的指数函数是ex,即自然对数函数的反数
-
Fri particular, the Wittmann-type strong law of larg numbers for independent random variables is generalized to the case of NA random variables. We also present the sufficient and necessary condition of the laws of logarithm, and we extend Teicher-type strong law of the large numbers for sequence of NA random variables. Some of the laws of iterated logarithm of Teicher-type, Egorov-type arid Wittmann-type for sequence of NA random variables are obtained. Then we investigate the rate3f ionvergcll( fbr series of NA randonl variables, we obtain soIne results fbr tl1e Iaws of theiterated logarithttl, the laws of logarithm and decreasing order fOr the tail sum.Risk itllttlysis tlleory is a sigIlifica11t part of insurance InatheInatics.
Wittmann(1985a)关于实独立随机变量列的结果,并给出了NA列强大数律成立的若干条件,特别建立了一般NA列对数律成立的充分必要条件,在二阶矩存在的条件下完整的解决了一般NA列对数律的问题,中文摘要2而已有的一些NA列对数律的结果可以由它推出,给出了NA列的Teiclier型强大数律,表明lbiChCI·(1979)给出的实独立随机变量列的强大数律可以减弱其条件等;建立厂不问分布NA列的Teicfl仪;Egorov,Petrov型有界重对数律,以及加权同分布NA列的有界重对数律,进一步推广了NA列的Kolmogory有界重对数律等,特别对NA列建立了Wittm洲型有界重对数律,而其证明方法与独立情形有很大不同,同时通过反例表明在与独立场合类似的条件下,独立列的Wittmann有界重对数律不能完美的推广到NA歹小惰形;最后研究了NA随机变量级数的收敛速度,给出了尾和下降的阶;尾和的有界重对数律,及尾和对数律成立的充要条件等,并通过反例说明 NA随机变量级数与独立随机变量级数在收敛速度方面存在的差异。
-
After analysis and study of characters of observational parameters of these extragalactic H2O megamaser sources, the correlations among them have been obtained as follows: lg S peak is anticorrelated with lg V sys and lg D , respectively.
通过对这些河外H2O超脉泽源的观测参数的特征的分析和研究,得到这些观测参数之间的相关关系为:河外H2O超脉泽源的峰值流量密度的对数分别与系统速度的对数和距离的对数之间存在着反相关关系。
-
In the heading stage and milking stage, the inferring ability of logarithm adding obviously surpasses that of SPAD value.
发现:在抽穗期和灌浆期,对数相加模型的反演能力明显优于SPAD值的反演能力。
-
3 By dose alkali in a two-pass RO system ; the formula can be used as a reference for design and debugging of the system to calculate the added alkali in two-pass RO .
本文根据水中碳酸平衡原理分析了反渗透系统产水pH值的变化,得出pH值下降量等于系统对HCO3-透过率的负对数的结果,并导出了在两级反渗透系统中加碱调节pH值至8。
- 推荐网络例句
-
On the other hand, the more important thing is because the urban housing is a kind of heterogeneity products.
另一方面,更重要的是由于城市住房是一种异质性产品。
-
Climate histogram is the fall that collects place measure calm value, cent serves as cross axle for a few equal interval, the area that the frequency that the value appears according to place is accumulated and becomes will be determined inside each interval, discharge the graph that rise with post, also be called histogram.
气候直方图是将所收集的降水量测定值,分为几个相等的区间作为横轴,并将各区间内所测定值依所出现的次数累积而成的面积,用柱子排起来的图形,也叫做柱状图。
-
You rap, you know we are not so good at rapping, huh?
你唱吧,你也知道我们并不那么擅长说唱,对吧?