半乳糖

This aberrancy exposes N-acetylgalactosamine-containing neoepitopes recognized by naturally occurring IgG or IgA1 antibodies resulting in formation of immune complexes.

这种异常暴露的包含新表位的N-端乙酰半乳糖胺能被自然产生的IgG或IgA1抗体识别而导致免疫复合物形成。

Locust bean gum (20% galactose) is more functional and more expensive than other galactomannan gums.

刺槐豆胶（半乳糖质量分数20%）与黄原胶的共混凝胶强度最大，也是价格最高的半乳甘露聚糖胶。

Methods The cognitive impairment rat model was induced by hypodermic D-galactose injection and half fat feeder (6 weeks), the Morris water maze was used to screen the model rats, which were divided randomly into 4 groups (12 rats in each group): the model group, the hydrochloricdonepezil group (0.4 mg/kg, weight, sic passim), the low-dose Huannao Yicong Fang group (7 g crude drug/kg), the high-dose Huannao Yicong Fang group (14 g crude drug/kg), they were treated respectively by intragastric administration. Besides, a control group of 12 rats was set up, they were given tales doses of distilled water. After 4 weeks, the behavior of the rats was detected, the contents of plasma P-selectin and PAI-1 were measured by ELISA, also the hemorrheology was measured.

采用皮下注射D-半乳糖及喂饲半高脂饲料（6周）的方法造成大鼠认知功能障碍，Morris水迷宫行为学测试确定模型成功的动物，随机分成四组（每组12只：模型对照组给予等量水，盐酸多奈哌齐组（0.4mg/kg，体质量，下同），还脑益聪方低剂量组（7g生药／kg），还脑益聪方高剂量组（14g生药／kg），同时灌胃给药，并设立正常对照组，给予等量水。4周后，对大鼠行为学检测，应用酶联免疫法检测大鼠血浆P-选择素及PAI-1含量和血液流变学各项指标。

Semiquantitative PCR analysis revealed that the levels of pectate lylase and β-galactosidase gene (MA-gal1) transcript were related with the banana fruit ripening and softening.

通过半定量PCR分析表明，所克隆的β-半乳糖苷酶基因（MA-gal1）和果胶裂解酶基因的表达与果实成熟软化相关。

The result demonstrated that mannitol was the best protective substance, followed by raffinose,trehalose and melibiose, L-cysteine, xanthan gum and glycerol showed slightly protective ability.

结果表明，甘露醇对α-半乳糖苷酶的保护效果最好，其次是棉籽糖、海藻糖和蜜二糖；L-半胱氨酸、黄原胶和甘油也起到了较好的保护作用。

The feasibility of determining the pentosan in pre-extraction liquor from eucalyptus chips by using Douglas colorimetric method was discussed in this paper. The visible spectrums of xylose, glucose, mannose, galactose and kraft lignin were compared under the same color reaction conditions. The results showed that the disturbance from hexoses and lignin can be eliminated when the pentosan is identified and determined by the maximal absorption at 553nm.

摘 要：探讨了 Douglas 比色法用于测定桉木半纤维素预提取液中戊聚糖的可行性，通过对木糖、葡萄糖、甘露糖、半乳糖和木素在相同条件下显色反应后的谱图进行比较，证明利用553 nm 处的最大吸收进行测定可以排除己糖和木素的干扰。

Galactose: A monosaccharide, CH2OH 4CHO, commonly occurring in lactose and in certain pectins, gums, and mucilages.

半乳糖：一种单糖，CH2OH 4CHO，一般产生于乳糖及特定的果酸、树胶及胶质物中

How does lactose bring about the induction of synthesis of β-galactosidase, permease, and transacetylase Why does this event not occur when glucose is also in the medium

乳糖如何诱导β-半乳糖苷酶、透过酶、转乙酰基酶合成的？为什么在葡萄糖存在的情况下，这一生物学事件不能发生？

For the E. coli lac operon, write the partial diploid genotype for a strain that will produceβ-galactosidase constitutively and permease by induction.

以大肠杆菌的乳糖操纵元为例，请写出一菌株的部分二倍体基因型：β-半乳糖苷酶是组成型表达的，透过酶是诱导表达的。

State Key Lab of Pulp and Paper Engineering,South China University of Technology,Guangzhou,Guangdong Province,510640) The fcasibility of determining the pentosan in pre-extraction liquor from eucalyptus chips by using Douglas colorimetric method was discussed in this paper.

探讨了Douglas 比色法用于测定桉木半纤维素预提取液中戊聚糖的可行性，通过对木糖、葡萄糖、甘露糖、半乳糖和木素在相同条件下显色反应后的谱图进行比较，证明利用553 nm处的最大吸收进行测定可以排除己糖和木素的干扰。

But we don't care about Battlegrounds.

但我们并不在乎沙场中的显露。

Ah! don't mention it, the butcher's shop is a horror.

啊！不用提了。提到肉，真是糟透了。