六个一组

Snake Road in particular disk array with the snake ring, that is, first came here the other maze using random, first spent a day run the whole way to understand and then use a random fly, snake ring array can also fly, so to be tied with eight random consumption mainly in the Snake Road site, snake ring that strange multi-burst, N is also more than the middle of the White Snake is a snake of five Hall, there are three White Snake Brush loafers, but there is also fierce private Qing Dynasty, the general or other练级then into the bar, the White Snake to kill more than the total return or, if it is with the Master Taoist group, then, the 33 best to find a good training or a hammer and then with the Road do not turn to anything, they may take a random healing with a row of a row of red, or Fu Road plus a bunch of people, with the two drugs package is enough, do not consume all the basic blue baby in the act, such as a hammer to go back 67 to take into account re-bills, following the easy to frequent high-level rebellion, or go back and re-recruit a good point, in short time would be to group the words that a law to go with the baby, then it is difficult to kill one would have to go back to tonic, and secondly a lot of bored people will come to steal the baby, even if you win PK drug consumption is now unavoidable, so the best fighters mixed with the Road , but here a man, if more than more than 9 in this练级individuals, then you do not intend to add on, and find it somewhere else, the least strange is the lack of Babel, against the devil, and not off-limits练级is to blame the other side of the same difficulty, but the experience is not how high.

尤其是盘蛇道跟蛇环阵，就是迷宫这里刚来的别用随机，先耗个两天跑跑路全搞清，然后才用随机飞，蛇环阵也可以飞的，所以要带八捆随机主要是耗在盘蛇道，蛇环这怪爆多，白蛇也N多中间是五蛇殿，刷白蛇还有三头蛇王，不过这里包场清人也比较凶，一般练级的话还是别进了吧，白蛇杀多了总还是有回报的，如果是法师跟道士组的话，法最好过33级找好锤子练升一级然后跟道去什么都不要背，就带随机跟一排疗伤一排红，道的符还是一捆加身上，毒带两大包足够了，蓝基本不耗都宝宝在做事，等锤子六七级时考虑回去重招，级高之后容易频繁叛变，还是回去重招好点，总之想待长时间的话一定要组道，一个法跟宝宝去的话是很难的，一来杀会就得回去补药，二来很多无聊的人会来偷宝宝，就算你PK赢了耗药是免不了的吧，所以还是战士跟道最好混了，不过这里得看人，要是超过九个人以上在这练级的话，那么你再加入就没意思了，找别的地方吧，怪最不缺的就是通天，逆魔了，不去禁地练级，是为了那边的怪一样难，但经验却不见得怎么高。

He runs for it, drives off, and leads the police on a long chase, something which Jack watches on television. Hurley is arrested and repeatedly cries that he is a member of the Oceanic 6. Hurley is brought to the police station, where Ana-Lucia's old partner Mike Walton, now a Detective, heart brokenly asks Hurley if he knew Ana Lucia Cortez (suggesting a romantic attraction). Hurley guiltily lies and claims to have never met her. Walton leaves, and Hurley looks onto the two-way mirror and sees Charlie drowning with the words "THEY NEED YOU" written in marker on his hand, much like the words "NOT PENNYS BOAT" were written in the finale of the third season. The mirror breaks and water come pouring out, and Hurley screams for help.

他跑开，驾车离开了，这导致一辆警车跟了他很久，而这些都被jack在电视上看见了。hurley被逮捕了，并且反复喊叫道他其实是"大洋六人组"的一员。hurley被带到了警察局，ana lucia的老搭档mike walton此时在这里任职侦探，他伤心地问hurley是否认识ana lucia cortez(可能是因为二者的一些爱情联系)。hurley充满罪恶感地否定了，并说从未听说过她。walton离开了以后，hurley看见双向玻璃镜里出现了溺水的chalie以及写在他手心的"他们需要你"这几个字，这场景非常像第三季最后出现的那个"不是penny的船"的画面。

This thesis is about the brand image of the mobile communication of the Chinese Mainland, using the internet to collect data by questionnaire survey. Do the factor analysis on the fifty six sample data, utilizing the software--SPSS. Find out the recessive variables, which are essential but can not be fathomable directly, hiding behind the fathomable variables.

本文就我国内地移动通信行业品牌形象这一主题设卷，通过网络问卷调查形式进行数据收集，利用SPSS统计软件，对五十六个样本数据进行因子分析，找出用来描述隐藏在一组可测量到的变量中的一些更基本的但又无法直接测量到的隐性变量。

In search of databases, the deduced products of sanP, sanQ, sanR, sanS, sanT and sanU show highest similarity to those of nikP2, nikQ, nikR, nikS, nikT and nikU of S. tendae respectively. In comparison with the proteins of identified function, it is indicated that sanP encodes a thioesterase, sanQ encodes a cytochrome P450, sanR encodes a uracil phosphoribosyltransferase, sanS encodes a carboxylase, sanT encodes a histidinol-phosphate aminotransferase and sanU encodes a mutase.

在蛋白数据库中比较结果表明，sanP、sanQ、sanR、sanS、sanT和sanU基因编码的蛋白分别和唐德链霉菌的尼可霉素生物合成基因nikP2、nikQ、nikR、nikS、nikT、nikU六个基因编码的蛋白同源性最高；根据和已知功能蛋白的比较，推测sanP基因编码的是硫酯酶，sanQ基因编码的是细胞色素P450，sanR基因编码的是尿嘧啶磷酸核糖转移酶，sanS基因编码的是羧化酶，sanT基因编码的是组氨醇磷酸氨基转移酶，sanU基因编码的是一种变位酶。

Chapter 5 and 6 are concentrated on the fundamental problem how to con-struct finite-dimensional and infinite-dimensional Liouville integrable Hamiltonsystem.Starting from two isospectral problems,Tu's scheme is applied to gen-erate the corresponding CKdV hierarohy and coupled Burgers hievachy,andthey are shown to be Liouville integrable Hamilton systems.Two spectral prob-lems,which contain three and four potentials respectively,are also studied byTu's scheme.Two new Liouville integrable Hamilton hierarchy are estab-lished.A new general approach using Lenard's gradient sequence is presentedto obtain Lax integrable hierarchy and their zero curvature representation,andsome examples are given.The nonlinearization procedure is applied to theeigenvalue problem of coupled Burgerrs hierarchy.It is shown that underBargmann constraint,the spatial part of the Lax pairs is nonlimearized to be afinite-dimensional Liouville completeiy integrable Hamilton system.

第五、六章研究如何从一个谱问题出发构造可积发展方程族及其零曲率表示、Hamilton结构和判断Liouville可积性：通过对二类具有2个位势的等谱问题直接研究，利用屠格式生成了耦合KdV族和耦合Burgers族，并证明它们均为Liouville可积的广义Hamilton方程族；而通过分别具有3个和4个位势的等谱问题，遵循屠格式构造了二族新的Liouville可积的广义Hamilton方程族；给出了利用Lenard梯度递推序列产生发展方程族及其零曲率表示的一种方法，作为应用，讨论了CKdV族，BPT族及耦合Burgers族的产生及其零曲率表示；应用非线性化技巧，证明了在Bargmann约束下，耦合Burgers族的Lax组可被线性化为Liou-ville完全可积的Hamilton系统。

24 I was giving a talk to a large group of people,the same talk I to half a dozen other groups.

因前一句的时态是过去时，而我给其他六个组做报告发生在给许多人做报告之前，故用过去完成时态。

The subjects of the research were four classes of 6th graders from an elementary school in Taipei City, dividing into an experiment group and a control group, two classes in each group. The course studied carried on quantitative analysis with the score of pretests, posttests and deferred tests to explore the results of learning between the experiment group and the control group and also carried on quality analysis with the concept maps and the information of interviews collected before, within, after the teaching to explore the concept transformation. Finally, researcher analyzed the advantages and disadvantages of applying the DAPA strategy in electromagnetic function with the data of observation and introspection. The important results of the study were summarized as below

研究对象为台北市郊区一所中型学校六年级四个班级，分为实验组、控制组各二个班，研究过程以学童的成就测验前、后、延宕后测成绩进行量化分析，探究实验组、控制组的学习成效是否达到显著差异；再以学童的教学前、中、后概念图、晤谈纪录进行质性分析，探究学童概念学习历程；最后依研究者自己的观察纪录与内省进行分析，找出DAPA教学策略应用在电磁作用单元时的优缺点，经研究后所得到的重要结果如下

One of the great discoveries of the study is that the MSC can be used to analyze and describe the complex reactions that both phase transformation and sintering happened at same time. In addition, using both our five-parameter S-curve fitting and German's three-parameter curve fitting lead to very similar results and values of Qa. Most importantly, we cannot find satisfactory data to support the hypothesis that Qa varies linearly either with particle diameter or with initial porosity of the samples.

在利用主导烧结曲线模型分析六组实验数据过程中，发现主导烧结曲线具有拟合烧结与相变同时发生之能力，此拟合曲线中包含了四个反应，包括anatase与anatase的烧结、anatase与rutile的烧结、rutile与rutile的烧结还有anatase的相变，此四种不同的反应竟然可以只由一条主导烧结曲线描述其变化，是本研究重要的发现。

The effect of free-fall on quality of the seed was studied by dropping six seed lots from four different heights on to cement and galvanized iron floors.

种子自由下落质量检测的效果是这样去衡量的，六个种子一组，从四个不同高度降落到水泥地和电镀铁地板上。

It's there, for instance, in The Calumny of Apelles , the drawing he did in 1565--the same year in which he painted the six great panels of the calmly changing seasons.

其内容，打个比方，就在《TheCalumny of Apelles》里。此画作于1565年，同年他还画了一组伟大的作品，就是表现季节在悄无声息中变化的那六幅。

With Death guitarist Schuldiner adopting vocal duties, the band made a major impact on the scene.

随着死亡的吉他手Schuldiner接受主唱的职务，乐队在现实中树立了重要的影响。

But he could still end up breakfasting on Swiss-government issue muesli because all six are accused of nicking around 45 million pounds they should have paid to FIFA.

不过他最后仍有可能沦为瑞士政府&议事餐桌&上的一道早餐，因为这所有六个人都被指控把本应支付给国际足联的大约4500万英镑骗了个精光。