偶数的

The even squares run in the opposite direction on a 45 degree angle, beginning with the square of 2, which is 4 and continuing on this angle.

这些是1，9，25，49，81，等。偶数的在其对面方向的45度角，起点是2的平方，这是从4开始的角度。

If two integers are both odd or both even, they are said to have the same parity; if one is odd and one even, they have different parity.

假如两个整数都是奇数或都是偶数，则它们具有相同的奇偶性；假如一个是奇数，一个是偶数，它们则具有相异的奇偶性

If two integer s are both odd or both even,they are said to have the same parity;if one is odd and one even,they have different parity.

假如两个整数都是奇数或都是偶数，则它们具有相同的奇偶性；假如一个是奇数，一个是偶数，它们则具有相异的奇偶性

The first is what are the fewest points of motion necessary to animal progression, the second why sanguineous animals have four points and not more, but bloodless animals more than four, and generally why some animals are footless, others bipeds, others quadrupeds, others polypods, and why all have an even number of feet, if they have feet at all; why in fine the points on which progression depends are even in number.

首先是运动是什么必要的动物进展最低分，第二个为什么血红的动物有四点意见，而不是多，但不流血的动物超过4，一般为什么一些动物是无足，其他两足动物，其他四足动物，其他polypods ，为什么都有一个偶数的脚，如果他们在所有的脚，为什么在精细点上的进展取决于更是增多。

If the imaginary line crosses an even number of boundary lines, the area can either be filled or not filled.

如果想象的线交叉过一条偶数的边界线，那么该区域可以是已填充的或未填充的。

Experiments indicate that,the arithmetic utilizing assistant matrix resolves the problem that even magic square can not figure out compared with Lauber arithmetic and De la Hire arithmetic,and can realize all even magic squares' resolution compared with using Greece Latina phalanx arithmetic.On the other hand,the arithmetic has sameness time complex degree and approving capability in figuring out odd magic square.

实验结果表明，利用辅助矩阵，该算法和劳伯利算法、哈利算法相比，解决了偶数阶魔方阵无法求解的问题，和利用希腊拉丁方阵算法相比，可实现全部偶数阶魔方阵的求解；另一方面，该算法在奇数阶魔方阵求解时具有相同时间复杂度和满意性能。

From these results, we can see that the Polignac-Xu's number is oscillatingly increased as even number increases. And this not only verified the conjecture mentioned above but offered a distinctly evidence for the former proof of it with mathematical induction also.

从计算结果可以看到，波利那克徐氏数是随着偶数的增大而振荡增大，这不但验证了这个猜测是不成立的，而且也给前期的数学归纳法证明提供了充分的依据。

Apply those properties to find the self-dual code of length 66, we got new extremal self-dual [66,33,12] code with β=32 for w1 and at least 50 inequivalent extremal self-dual [66,33,12] codes with .

我们推广Harada[4]的一个建构自对偶码的定理，Harada[4]的方法在[2n，n]， n为偶数的条件下方可成立，而我们推广出的定理可以适用於n为奇数的情况。

Harmonic frequencies and infrared spectra intensity for these clusters are given in order to aid in the characterization of the ground states. The results show that Si2CmN(m=2-10) clusters form linear structure, which are doublet states. The Si atoms favor to bond at ends of C and N linear chain. The ground state energies of clusters are nearly in proportion to increased m. The stability of Si2CmN(m=2-10) clusters with even m are greater than that with odd m.

结果表明，m=2-10的团簇为线性结构，随着m的增大，团簇的自旋多重度均为2，Si原子在C与N原子形成的线性链端部成键，团簇的基态能量近似线性增大。m为偶数的Si2CmN团簇比m为奇数的更为稳定。

The paper researches into the cognitive and neural mechanism of the language switch of bilinguals as follows:(1) word association test of L1 and L2 mental lexicon;(2) neighborhood effect test of the bilinguals;(3) MSIT with Stroop, Simon and Flanker combined;(4) behavioral experiment of the even-odd number language switch;(5) ERP experiment of the even-odd number language switch.

本文将从以下几个角度研究双语者语码转换过程中的认知神经机制。(1)L1和L2大脑词库词汇联想测试；(2)中英双语被试家族词汇行为实验；(3)Stroop、Simon和Flanker多源冲突实验；(4)奇偶数汉英语码转换行为实验；(5)奇偶数汉英语码转换ERP实验。

With Death guitarist Schuldiner adopting vocal duties, the band made a major impact on the scene.

随着死亡的吉他手Schuldiner接受主唱的职务，乐队在现实中树立了重要的影响。

But he could still end up breakfasting on Swiss-government issue muesli because all six are accused of nicking around 45 million pounds they should have paid to FIFA.

不过他最后仍有可能沦为瑞士政府&议事餐桌&上的一道早餐，因为这所有六个人都被指控把本应支付给国际足联的大约4500万英镑骗了个精光。