任一

Theorem Let M be a orientable or non-orientable closed surface, and f a C°-flow whose every singular point is isolated. Then f has POTP if and only if the following three conditions hold

定理 设M是任一个可定向或不可定向的闭曲面，f是M上任一个奇点均孤点的C〓-流，则f具有伪轨跟踪性质的充分必要条件是

Numerical solution of the model is maed by using Monte-Carlo sampling method.Its solution is astochastic field. It is showed by a real case that the model can describe the main trend and changing range ofpollutant'sconcentration at any calculating point,and the probability is added to the isopleth of the pollutant'sconcentration.

该随机模型的解是一个随机场，实例计算表明，它的解能够反映任一计算点的浓度变化趋势及范围，并能够给程度等值线附加上概率的意义，表现了在不确定因素的影响下，污染带随机变化的情况。

Adopting generalized Jordan block and algebra equivalence transform method, all of the transfer functions at different load points can be transformed to state-space description with time variable. The steady robustness of three different mode of control systems were researched by mathematic analysis. It shows that: for the high order inertia controlled object with the characteristic of nonlinear and time-variable that described by the set of transfer functions, the Luenberger function observer established according to its any algebra equivalence state-space description, if some conditions can be met, there would be a matrix of T with n′n satisfied the Sylvester matrix equation TA- FT=GC.

采用广义约当块及代数等价变换方法，可将分段的传递函数描述转换为变参数的状态空间描述，对3种典型控制系统的稳定鲁棒性所进行的理论研究表明，对同一组传递函数描述的具有非线性和时变特性的高阶惯性受控对象，依据其任一代数等价的状态空间描述所构建的Luenberger函数观测器，在满足一定的条件时，存在n′n解阵T满足Sylvester矩阵方程TA- FT=GC。

Neither team has control of the ball nor was entitled to the ball, a jump ball situation occurs.

任一队没有控制球也没有球权，一次跳球情况发生

Neither team had control of the ball nor was entitled to the ball, a jump ball situation occurs.

任一队都没有控制球也没有球权，一次跳球情况发生。

After that,the adverse search is carried on to each information,if there is any break found,this jump operation may have the possibility of deadlock,otherwise it is regarded as connected and the jump is living.

然后对每一条进行逆向搜索，若发现任一处信息断链，则该转移操作有可能发生死锁；否则认为通达，该转移是活的。

If you can be the first to solve any of these puzzles, you will be justifiably famous.

如果你能成为解决其中任一谜题的第一人，你将会有理由出名。

Any plant of the genus Kalmia.

属于美国石南科的任一植物。

Any of various similar cetaceans, such as the killer whale.

虎鲸多种类似的鲸类动物中的任一种，如虎鲸

Then with these two equations, we can eliminate K and solve for output as a function of L (and also R, which a nation takes as given).

有了这两个等式，消掉 K ，得到产出是 L 的函数（当然，也是 R 的函数。对任一个国家来说， R 可以当作给定的）。

I didn't watch TV last night, because it .

昨晚我没有看电视，因为电视机坏了。

Since this year, in a lot of villages of Beijing, TV of elevator liquid crystal was removed.

今年以来，在北京的很多小区里，电梯液晶电视被撤了下来。