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For most of them,fifty pence is a small price to pay for a satisfying bar of chocolate.

对大部分孩子来说，用50便士来买一大块好的巧克力，是算不了什么的。

First, we introduce and discuss the various methods of multivariate polynomial interpolation in the literature. Based on this study, we state multivariate Lagrange interpolation over again from algebraic geometry viewpoint:Given different interpolation nodes A1,A2 .....,An in the affine n-dimensional space Kn, and accordingly function values fi(i = 1,..., m), the question is how to find a polynomial p K[x1, x2,...,xn] satisfying the interpolation conditions:where X=(x1,X2,....,xn). Similarly with univariate problem, we have provedTheorem If the monomial ordering is given, a minimal ordering polynomial satisfying conditions (1) is uniquely exsisted.Such a polynomial can be computed by the Lagrange-Hermite interpolation algorithm introduced in chapter 2. Another statement for Lagrange interpolation problem is:Given monomials 1 ,2 ,.....,m from low degree to high one with respect to the ordering, some arbitrary values fi(i= 1,..., m), find a polynomial p, such thatIf there uniquely exists such an interpolation polynomial p{X, the interpolation problem is called properly posed.

文中首先对现有的多元多项式插值方法作了一个介绍和评述，在此基础上我们从代数几何观点重新讨论了多元Lagrange插值问题：给定n维仿射空间K~n中两两互异的点A_1，A_2，…，A_m，在结点A_i处给定函数值f_i(i=1，…，m)，构造多项式p∈K[X_1，X_2，…，X_n]，满足Lagrange插值条件：p=f_i，i=1，…，m (1)其中X=(X_1，X_2，…，X_n)，与一元情形相似地，本文证明了定理满足插值条件(1)的多项式存在，并且按"序"最低的多项式是唯一的，上述多项式可利用第二章介绍的Lagrange-Hermite插值算法求出，Lagrange插值另一种描述是：按序从低到高给定单项式ω_1，ω_2，…，ω_m，对任意给定的f_1，f_2，…，f_m，构造多项式p，满足插值条件：p=sum from i=1 to m=Ai=f_i，i=1，…，m (2)如果插值多项式p存在且唯一，则称插值问题适定。

The subjective nature of the utility concept 15 , however , susceptible to ordinal ranking measure . 12 In ordinal preference patterns , one only has to be able to rank alternatives 一from highest to lowest , best to worst , or most satisfying to least satisfying ; no attempt 15 made to quantify the amount by which one alternative 15 better than others - Despite the fact that utility 15 not subiect to precise quantification , it 15 still analytically useful to assume that utility can be represented by cardinal numbers .

公共概念15 的主观本质，然而，易受影响序数等第措施。12 在序数特选样式，你必须只能排列选择一从最高对最低，最好对最坏，或令人满意对最少满意；企图15 没有做定量一个选择15 更好的数额比其他人-竟管公共事业15 不是subiect 写量化，它的大意15 寂静分析有用假设，公共事业可能由序数代表。

At each database sites, sampling algorithm and constrained Eclat algorithm are implemented. And the local frequent itemsets satisfying constraints are developed. They then are combined to global frequent itemsets that satisfying constraints based on learning from induction.

算法在各数据站点上对一个较小的样本采用基于约束的Eclat类算法挖掘局部约束频繁项集，用归纳学习的方法归并所有局部约束频繁项集产生全局约束频繁项集。

Firstly, the equation for stress intensity factors under static uniform pressure is used as the reference case, and then the weight function for a thick-walled cylinder containing a radial edge crack can be worked out. Secondly, the dynamic stresses in uncracked thick-walled cylinders are solved under internal impulsive pressure by using mode shape function method. The solution consists of a quasi-static solution satisfying inhomogeneous boundary conditions and a dynamic solution satisfying homogeneous boundary conditions, and the history and distribution of dynamic stresses in thick-walled cylinders are derived in terms of Fourier–Bessel series. Finally, the dynamic stress intensity factor equations for thick-walled cylinder containing a radial edge crack subjected to internal impulsive pressure are given by dynamic weight function method.

首先采用静态内压下的应力强度因子作为参考解，得到了带径向边裂纹厚壁圆筒的权函数；然后用振型函数方法推导无裂纹厚壁圆筒在冲击内压下的动应力响应，分析中将相应的弹性动力学方程解分为满足非齐次边界条件的准静态解和满足齐次边界条件的动态解的叠加，利用傅立叶-贝塞尔级数展开，推导出了厚壁圆筒内动应力的响应历程和分布规律；最后由动应力权函数方法导出带径向边裂纹厚壁筒在冲击内压下的动态应力强度因子计算公式。

Based on introducing the conceptions of linguistic judgment matrix and its satisfying consistency, a judgment method is presented to judge whether the linguistic judgment matrix with exacting preference relation has satisfying consistency.

但由于判断事物的模糊性和不确定性，判断矩阵中的元素有时无法用确定的数值表示，而采用自然语言短语表示则更为方便[1]。

Intercourse self-satisfying: 72.2% of all the poverty college students'enjoy a high self-satisfying in intercourse action with the college mates, different in the grade、sex and major, 62.8% of students'enjoy a normal self-satisfying in intercourse action with the teacher , different in the grade、sex and major.

交往的自我效能感：72.7%的贫困大学生与朋友交往的自我效能"高"，年级、性别和专业方面均存在显著差异；62.8%贫困大学生与教师交往的自我效能感"一般"，年级、性别和专业方面均存在显著差异。

Not only n satisfying FCC mask by schematized version but also a range of α which satisfy the regulation can be figured out by the proposed algorithm, The proposed algorithm in this paper can figure out not only n satisfying FCC mask by schematized version but also a range of α which satisfy the regulation, t hat is to say, which means it can scheme out a myriad of pulses that are compliant can be designed .

在满足频谱模板的情况下此算法能求出α的一个范围，即可以设计出无数个满足 FCC 频谱规划的脉冲。

First, we introduce and discuss the various methods of multivariate polynomial interpolation in the literature. Based on this study, we state multivariate Lagrange interpolation over again from algebraic geometry viewpoint:Given different interpolation nodes A1,A2 .....,An in the affine n-dimensional space Kn, and accordingly function values fi(i = 1,..., m), the question is how to find a polynomial p K[x1, x2,...,xn] satisfying the interpolation conditions:where X=(x1,X2,....,xn). Similarly with univariate problem, we have provedTheorem If the monomial ordering is given, a minimal ordering polynomial satisfying conditions (1) is uniquely exsisted.Such a polynomial can be computed by the Lagrange-Hermite interpolation algorithm introduced in chapter 2. Another statement for Lagrange interpolation problem is:Given monomials 1 ,2 ,.....,m from low degree to high one with respect to the ordering, some arbitrary values fi(i= 1,..., m), find a polynomial p, such thatIf there uniquely exists such an interpolation polynomial p{X, the interpolation problem is called properly posed.

文中首先对现有的多元多项式插值方法作了一个介绍和评述，在此基础上我们从代数几何观点重新讨论了多元Lagrange插值问题：给定n维仿射空间K~n中两两互异的点A_1，A_2，…，A_m，在结点A_i处给定函数值f_i(i=1，…，m)，构造多项式p∈K[X_1，X_2，…，X_n]，满足Lagrange插值条件：p=f_i，i=1，…，m (1)其中X=(X_1，X_2，…，X_n)，与一元情形相似地，本文证明了定理满足插值条件(1)的多项式存在，并且按&序&最低的多项式是唯一的，上述多项式可利用第二章介绍的Lagrange-Hermite插值算法求出，Lagrange插值另一种描述是：按序从低到高给定单项式ω_1，ω_2，…，ω_m，对任意给定的f_1，f_2，…，f_m，构造多项式p，满足插值条件：p=sum from i=1 to m=Ai=f_i，i=1，…，m (2)如果插值多项式p存在且唯一，则称插值问题适定。

Firstly, it stimulates the industrialization and structure adjustment of wood products through satisfying the all kinds of demands. Secondly,it stimulates the adornment industry through satisfying demands of adornment. Thirdly, it takes active role in enlarge the wood floorboards market and relaxing employment pressure by means of the nature of wooden floorboards industry-a kind of concentrated laboring trade. Fourthly, it reasonably takes advantage of wood resources and saves on wood, through improving the scale of enterprises. These are beneficial to protection of forest resources. Fifthly, it plays role in protection of life and environment, through its stimulating construction of wood material base.

首先，通过满足木地板多元化的需求，促进林产工业产业化和林产品的结构调整；其次，通过木地板对装饰行业的配套作用，满足装饰行业的需求，促进装饰行业的发展；第三，积极拓展，增大木地板市场规模，利用木地板行业劳动密集型特点增加就业机会缓解就业压力；第四，通过对木地板行业的规模化发展及可持续发展战略的推动，合理利用资源，节约木材，有利于森林资源保护；第五，通过大力发展木地板行业，推动原料林基地建设，对我国的生态环保做出一定的贡献。

We have no common name for a mime of Sophron or Xenarchus and a Socratic Conversation; and we should still be without one even if the imitation in the two instances were in trimeters or elegiacs or some other kind of verse--though it is the way with people to tack on 'poet' to the name of a metre, and talk of elegiac-poets and epic-poets, thinking that they call them poets not by reason of the imitative nature of their work, but indiscriminately by reason of the metre they write in.

索夫农 、森那库斯和苏格拉底式的对话采用的模仿没有一个公共的名称；三音步诗、挽歌体或其他类型的诗的模仿也没有——人们把&诗人&这一名词和格律名称结合到一起，称之为挽歌体诗人或者史诗诗人，他们被称为诗人，似乎只是因为遵守格律写作，而非他们作品的模仿本质。

The relationship between communicative competence and grammar teaching should be that of the ends and the means.

交际能力和语法的关系应该是目标与途径的关系。