查询词典 over and over again

First, we introduce and discuss the various methods of multivariate polynomial interpolation in the literature. Based on this study, we state multivariate Lagrange interpolation over again from algebraic geometry viewpoint:Given different interpolation nodes A1,A2 .....,An in the affine n-dimensional space Kn, and accordingly function values fi(i = 1,..., m), the question is how to find a polynomial p K[x1, x2,...,xn] satisfying the interpolation conditions:where X=(x1,X2,....,xn). Similarly with univariate problem, we have provedTheorem If the monomial ordering is given, a minimal ordering polynomial satisfying conditions (1) is uniquely exsisted.Such a polynomial can be computed by the Lagrange-Hermite interpolation algorithm introduced in chapter 2. Another statement for Lagrange interpolation problem is:Given monomials 1 ,2 ,.....,m from low degree to high one with respect to the ordering, some arbitrary values fi(i= 1,..., m), find a polynomial p, such thatIf there uniquely exists such an interpolation polynomial p{X, the interpolation problem is called properly posed.

文中首先对现有的多元多项式插值方法作了一个介绍和评述，在此基础上我们从代数几何观点重新讨论了多元Lagrange插值问题：给定n维仿射空间K~n中两两互异的点A_1，A_2，…，A_m，在结点A_i处给定函数值f_i(i=1，…，m)，构造多项式p∈K[X_1，X_2，…，X_n]，满足Lagrange插值条件：p=f_i，i=1，…，m (1)其中X=(X_1，X_2，…，X_n)，与一元情形相似地，本文证明了定理满足插值条件(1)的多项式存在，并且按"序"最低的多项式是唯一的，上述多项式可利用第二章介绍的Lagrange-Hermite插值算法求出，Lagrange插值另一种描述是：按序从低到高给定单项式ω_1，ω_2，…，ω_m，对任意给定的f_1，f_2，…，f_m，构造多项式p，满足插值条件：p=sum from i=1 to m=Ai=f_i，i=1，…，m (2)如果插值多项式p存在且唯一，则称插值问题适定。

The hypochondriac afflatus is subsiding; the acres, which in imagination I had spread over -- for the sick man swells in the sole contemplation of his single sufferings, till he becomes a Tityus to himself -- are wasting to a span; and for the giant of self-importance, which I was so lately, you have me once again in my natural pretensions -- the lean and meagre figure of your insignificant Essayist.

该hypochondriac afflatus是下沉；英亩，这在我的想象摊-为病夫膨胀，在唯一的沉思，他单身的痛苦，直到他成为一个提提俄斯自己-是在浪费一个跨度；为巨人自我的重要性，这点我是如此，最近，你有我再次在我的自然伪装-精益和微薄的数字，您的微不足道的散文家。

I also wanted to show you that the swan I accidentally stepped on over at Alexandrite's is all right, and we are friends again.

我也想表现出你天鹅我不小心，加强对超过在翠绿宝石的，是所有权利，我们是好友。

Again, position it over the second circle, select both shapes, click the large circle and align to vertical center.

同样放置在第二圈上，选择两个形状，单击大圆圈，垂直中心对齐。

You are wrong and you'll have to do it all over again.

你错了，你得重做一遍。

And I've lost her all over again.

我已经失去了她所有了。

And if you find you are not , I hope you have the strength to start all over again .

如果你想象的生活不一样，我希望你能有勇气重新启程。

And then, do it all over again

还因为，为了你，我能做的事

Tech-industrialist Max Winters is amassing an army of ancient monsters to apparently take over the world. And only one super-ninja fighting team can stop them-those heroes in a half shell-Leonardo, Michelangelo, Donatello and Raphael! With the help of old allies April O'Neil and Casey Jones, the Turtles are in for the fight of their lives as they once again must face the mysterious Foot Clan, who have put their own ninja skills behind Winters' endeavors.

当技艺家产家马克斯·温特斯开始组建一支由陈腐的怪兽组成的部队妄图统治六合的时间，李奥纳多、米开朗基罗、多纳泰罗和拉斐尔在他们的老同伴爱普里尔奥尼尔和凯西琼斯的帮助下，又重新团结到一起，协作反抗雠敌，并再一次面对与奇奥的大脚忍者兵的寻衅。

To conclude I would like to once again browse over the factors covered during the course of my series on conflict in Jammu and Kashmir and would like to remind you that conflicts have become a part of our system and we have to cope up with this new challenge by essentially being watchful.

最后我想再次浏览其他因素盖在我的系列课程在查谟和克什米尔冲突和矛盾想提醒大家，已经成为我们系统我们必须适应这种新的挑战，基本上与小心翼翼。

The concept of equivalent rotationally rigidity is offered and the formula of rotationally rigidity is obtained.

主要做了如下几个方面的工作：对伸臂位于顶部的单层框架—筒体模型进行分析，提出了等效转动约束的概念和转动约束刚度的表达式。

Male cats normally do not need aftercare with the exception of the night after the anesthetic.

男猫通常不需要善后除了晚上的麻醉。