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Practical microstrip antenna problems, such as the effect of superstrate on input impedance and radiation pattern are studied.

根据所得的新公式建立了多层介质覆盖矩形贴片微带天线的积分方程，并利用有效的数值技术求解出上述方程，得到了贴片上的电流分布，进而求出天线输入阻抗和辐射方向图。

If IT represents high input but low yield, of course, the enterprises would not be enthusiastic on investment in IT.

如果信息化给人的印象是高投入而产出不明显，企业投入的热情不会高。

Even where America and China do compete, as in electronics, the high import content of China's exports blunts the impact of exchange-rate movements on export prices, because a rise in the yuan reduces input costs.

就算在中美间确有竞争的领域，由于人民币升值减少了投入的成本，中国出口商品的极高的进口构成也会钝化汇率变化对出口价格的影响。

Even where America and China do compete, as in electronics, the high import content of China's exports blunts the impact of exchange-rate movements on export prices, because a rise in the yuan reduces input costs.

但即使在这些领域中，由于中国出口品之中的进口含量很高，这就削弱了汇率变化对出口价格的影响，因为人民币升值会降低中国的进口成本。

A multiplayer chip LC resonator was fabricated using planar inductor and parallel plate capacitor. Because lumped inductor has small Q value and there is stray parameter effect in high permittivity substrate, the Q value of chip LC resonator is not high. Resonators based on λ/4 stripline with end short circuited were designed and fabricated. Input and output pads, coupled to the stripline using gap-coupling capacitor, are in the same layer with the center conductive strip. This new structure is very convenient for manufacturing in comparison with the conventional structure.

采用间隙电容耦合结构实现的谐振频率为1.8GHz四分之一波长终端短路带状线单端口谐振器的Q值最大值为225，谐振频率为1GHz双端口谐振器的Q值为83，谐振频率和Q值与耦合间隙、带状线的厚度和耦合引线长度有关；二分之一波长带状线谐振器的Q值和四分之一波长相比较尺寸较大，由于导电带较长，造成金属的损耗增加，从而导致谐振器的Q值较低；带状线结构的谐振器频率调节困难，本文提出了改变接地端的宽度实现谐振频率的微调方法，可实现频率调节量约1.5%。

Through circularly exporting certain electrical levels on the rows of matrix keyboard, the electrical levels of the lines will be read, then the aim of scanning matrix keyboard will be realized by comparing the output and input. As the electrical level array of rotary keyboard is different when positive and negative circumvolving, the direction can be judged by comparing the electrical level of A and B phase.

本题目利用Mega16单片机以及外围电路，以C程序设计语言为基础，通过使矩阵式键盘的行端口循环输出一定的电平，接着读取列端口的电平，经过比较就可以实现对矩阵式键盘的扫描，因为旋转编码器的正反方向输出电平序列的不同，因此通过对其输出端A和B的相位进行比较即可实现对旋转编码器的方向判定。

One program that illustrates the need for such operations is cat, which concatenates a set of named files into the standard output. cat is used for printing files on the screen, and as a general-purpose input collector for programs that do not have the capability of accessing files by name.

程序cat可以用来说明该问题，它把一批命名文件串联后输出到标准输出上。cat可用来在屏幕上打印文件，对于那些无法通过名字访问文件的程序来说，它还可以用作通用的输入收集器。

Based on the model, the formula of the steady-state and transient response conduced by phase step input was deduced.

源代码开放的结构，易于进行升级与扩充，为以后类似的工作提供很好的参考。

Since Gabor feature is robust to illumination and expression variations and has been successfully used in face recognition area. First, the proposed method decomposes the normalized face image by convolving the face image with multi-scale and multi-orientation Gabor filters to extract their corresponding Gabor magnitude maps. Then, the local binary patterns operates on each GMM to extract the local neighbor pattern. Finally, the input face image is described by the histogram sequence extracted from all these region patterns.

鉴于Gabor特征对光照、表情等变化比较鲁棒，并已在人脸识别领域得到成功应用，首先对归一化的人脸图像进行多方向、多分辨率Gabor小波滤波，并提取其对应不同方向、不同尺度的多个Gabor幅值域图谱(Gabor magnitude map，简称GMM)，然后在每个GMM上采用局部二值模式(local binary pattern，简称LBP)算子抽取局部邻域关系模式，最后由这些模式的区域直方图形成的序列来描述人脸。

We begin with your input on what your most important keywords are, then expand that list by cross-checking the list against the search engines' databases of actual keyword searches.

开始我们会与您一起输入确定你的最重要的关键词，然后通过对搜索引擎数据库中的实际关键词搜索分析，而展开关键词的交叉核对名单。

Singer Leona Lewis and former Led Zeppelin guitarist Jimmy Page emerged as the bus transformed into a grass-covered carnival float, and the pair combined for a rendition of "Whole Lotta Love".

歌手leona刘易斯和前率领的飞艇的吉他手吉米页出现巴士转化为基层所涵盖的嘉年华花车，和一双合并为一移交&整个lotta爱&。

This is Kate, and that's Erin.

这是凯特，那个是爱朗。