查询词典 n.F.

This paper investigates the absolute convergence of the Fourier Laplace series concerning of some smooth functions defined on the unit sphere in R n,hereinto shows that:if f is 2([n4]+1) th continuously differentiable function on H r P,then the series ∑∞k=0Y kf converges uniformly to f.

讨论了n 维球面上某些可微函数类的Fourier Laplace级数的绝对收敛性，其中指出：设f是Hrp上 2 ( [n4 ]+1)次连续可微函数，则级数∑∞k =0 Ykf一致收敛到f参

Let H. f and g be real polynomials in x, y of degree n+1, at most n and at most n respectively,△ be a set of h such that the real algebraic curve H =h has a compact component δ, and ω=gdx-fdy be a polynomial 1-form.

设H是n+1次实多项式，f，g为至多n次的实多项式，记△为使实代数曲线H=h有一个紧分支δ的所有h之值的集合，ω=gdx-fdy为多项式1-形式。

Then the coefficients of entrance region effect and the relations between them, and the flowbehaviour index n can be obtained by solving the energy integral equation. Under the assumption of the velocity distribution within boundary layer: f = 1-(1-η)n+1/n for example, co...

以边界层内幂律流体层流速度分布假设f=(1一η)~(n+1/n为特例，所求出的结果与文献[4]中的理论值和实验值比较表明，本文的计算是既简便又可靠的。

Finally, the author proves the sharp bound for the indices of convergence of n*n reducible Boolean matrices with f〓≥2 the writer lets f〓 be the greatest common divisor of the distinct lengths of the elementary cycles of the associated digraph D (A for a reducible Boolean matrix A , and characterizes the matrices with the largest index.

最后，设f〓为可约布尔矩阵A的伴随有向图D的所有圈长的最大公约数，当f〓≥2时，我们得到了可约布尔矩阵幂敛指数的一个上界和达到最大幂敛指数的矩阵的完全刻划。

If deg f = n, then Rfc is an empty set. For all the functions of degree 2, Rf have at least 2n-1 vectors, when Rf is a linear subspace, the relationships between Rf and Lf are discussed . Boolean functions have no nonezero linear structure if and only if there are n linear independence vectors in f, the correlation of the vectors in ?

证明了，若degf=n，则R_f~c为空集，对于所有的二次布尔函数而言，均有R_f~c中的元素个数大于等于2~(n-1)，给出了R_f构成线性子空间时，R_f和L_f之间的关系，还给出布尔函数不含有非零线性结构的充分必要条件是ζ_f中含有n个线性无关的元素。

Firstly, we study the normality of a family of meromorphic functions concerning differential polynomial and shared values and prove the following Theorem 23.5 Let F be a family of m...

证明了 定理 2.3.5设F为Δ上亚纯函数，k、n、q∈N，P=ω~q+α_(q-1)ω~(q-1)+…+α_1ω是多项式，并且设Hf，f~1，…，f~(k是不含常数项的多项式，a、b为两个判别的有穷复数，并且b≠0，c是非零有穷复数。

The constituents of bulb of F. puqiensis were studied. Five steroid alkaloids were isolated. The plane structure and stereoscopic configuration of 4 compounds were elucidated. They are named as puqienine A (FP-33), puqienine B (FP-3), N-demethyl-puqietinone (〓 FP-34) and puqietinone (〓, FP-9). Puqienine A and N-demethyl-puqietinone are new compounds. Puqienine B is as same as FPQ-3 elucidated by Prof.

对F.puqiensis鳞茎化学成份进行了研究，分得5个甾体类生物碱成分，并采用 UV、IR、EI-MS、1D-NMR，HHCOSY、CHCOSY、HMBC和X-RAY等光谱技术和理化常数测定，鉴定出4个化合物的平面结构和立体构型，分别为蒲圻贝母碱甲（puqienineA，FP-33）、蒲圻贝母碱乙（puqienineB，FP-3）、N-去甲蒲贝酮碱（N-demethyl-puqietinone，FP-34）和蒲贝酮碱（puqietinone，FP-9），其中蒲圻贝母碱甲和N-去甲蒲贝酮碱为新化合物。

It is proved in this paper that R/ is a principal ideal domain, where R=F+uF+…+u(superscript k-1)F, n is odd, and p is a prime number, and some necessary and sufficient conditions for the cyclic codes over R to be self-dual are given.

该文证明了R/是主理想环，其中R=F+uF+…+u(上标 k-1)F，n是奇数，p为素数，给出了环R上循环码是自对偶码的充要条件。

Artist : Lady Sovereign Title : Love Me Or Hate Me Album : N/A Genre : Modern Rock Email this page to a friend Yeah It's officially the biggest midget in the game... I dunno Make way for the Ess Oh Vee Love me or hate me it's still an obsession Love me or hate me that is the question If you love me then thank you If you hate me then f**k you x 2 I'm fat I need a diet Na in fact I'm just too light and I aint got the biggest breast-s-s But I wrote all the best disses I got hairy armpits But I don't walk around like this I wear a big baggy T-shirt That hides that nasty sh*t Ugh... never had my nails done Bite them down until they're numb I'm the one with a non-existent bum I don't really give a UGH I'm missing my shepherd's pie Like a high maintenance chick missing her diamonds I'm missing my Clipper lighters Now bow down to your royal highness No, I don't own a corgi I had a hampster It died cos I ignored it Go on then, go on report me I'm English, try and deport me Love me or hate me it's still an obsession Love me or hate me that is the question If you love me then thank you If you hate me then f**k you x 2 I'm a funky little monkey With the tiniest ears I don't like drinking fancy champi I stick with Heineken beers Oops, might burp in your face A little unladylike, what can I say?

标题： 爱我或恨我册页： N/A 风格：现代岩石给这页发电子邮件给朋友呀它正式地是最大的侏儒在比赛… I dunno做方式为Ess Oh Vee 爱我或恨它是成见仍然爱我的我或恨我是问题，如果您爱我然后感谢您，如果您恨我然后f ** k您x 2 我是肥胖的我需要饮食Na实际上我是太轻的，并且I aint得到了最大的乳房s s，但我写了我得到长毛的腋窝的所有最佳的disses，但我不象我穿着一件大宽松的T恤杉掩藏那讨厌的sh*t Ugh…的这样走动未曾安排我的钉子做咬住他们下来，直到他们麻木我是那个与一不存在二赖子我真正地不给我错过我的牧羊人的饼象错过她的金刚石的一只高效维护小鸡我错过我的飞剪机打火机现在压垮对殿下没有的UGH，我没拥有我有一hampster它死COS我在报告忽略它然后继续，去我我英语，尝试并且递解我的corgi 爱我或恨它是成见仍然爱我的我或恨我是问题，如果您爱我然后感谢您，如果您恨我然后f ** k您x 2 我一只质朴的小的猴子是否是用我不喜欢喝花梢champi I棍子用Heineken啤酒Oops的最微小的耳朵，也许打嗝在您面对A少许unladylike，我什么能说？

The main results are:In logic system ,G,tautologies can not be get by using upgrade algorithm to non tautologies within finite many times;In logic system G n,tautologies can be get by using upgrade algorithm to an arbitrary formula of F at most n times; Congruence partitions about on F have been given in logi...

主要结果是：在逻辑系统 G，G中，重言式不可能由对非重言式进行有限次升级算法得到；在逻辑系统 Gn 中，对任一公式最多进行 n次升级算法即可得到重言式；利用可达广义重言式概念和α-矛盾式概念分别在 G，G，Gn 中给出了 F的一个关于同余的分划。

The split between the two groups can hardly be papered over.

这两个团体间的分歧难以掩饰。

This approach not only encourages a greater number of responses, but minimizes the likelihood of stale groupthink.

这种做法不仅鼓励了更多的反应，而且减少跟风的可能性。