查询词典 let be

Theorem Let be a function of period . If satisfies the convergent theorem, the Fourier series of is

定理 设周期为的周期函数满足收敛定理的条件，则它的傅立叶级数展开式为

Let be a compact pseudo-umbilical submanifolds with parallel mean curvature vector in the quasi constant curvature space.

设Mn是拟常曲率空间Nn+p中具有平行平均曲率向量的紧致伪脐子流形，论证得到了这种子流形的两个内蕴积分不等式，从而给出了Mn是全脐子流形的两个内蕴充分条件。

Let be defined on the open interval for some. If is differentiable at, and for any in

设函数在点的某邻域内有定义，并且在处可导，如果对任意的，有，那么。

Theorem Let be differentiable at. Then has a directional derivative at in any direction and

定理 如果函数在点可微分，那么函数在该点沿任一方向的方向导数存在，且有

The game that OnLive can let be abounded complexly with the graph is clear on low end PC and other equipment emersion.

OnLive能让复杂的和图形丰富的游戏在低端PC和其他设备上清晰再现。

Property 2 Let be a continuous function of several variables on a closed region D, then can obtain any number between its absolute maximum M and its absolute minimum m.

性质2在有界闭区域D上的多元连续函数，必定在D上取得界于最大值M与最小值m之间的任何值。

Property 1 (Boundedness and max-min theorem) Let be a continuous function of several variables on a closed region D, then has an absolute maximum and an absolute minimum on the region.

性质1（有界性与最大值最小值定理）在有界闭区域D上的多元留恋许函数，必定在D上有界且一定能取得它的最大值和最小值。

Let be the maximum of the function , find the value of .

设是函数的最大值，求的值。

Let be a sequence of independent and identically distributed random variables,with mean and variance .

Corollary 4.2 设相互独立的随机变量服从同一分布，已知均值为，方差为。

Let be a sequence of independent and identically distributed random variables,and ,exist ,then,for any value ,.

Corollary 4.1 设相互独立的随机变量有相同的分布，且，存在，则对于任意正整数，有。

With Death guitarist Schuldiner adopting vocal duties, the band made a major impact on the scene.

随着死亡的吉他手Schuldiner接受主唱的职务，乐队在现实中树立了重要的影响。

But he could still end up breakfasting on Swiss-government issue muesli because all six are accused of nicking around 45 million pounds they should have paid to FIFA.

不过他最后仍有可能沦为瑞士政府&议事餐桌&上的一道早餐，因为这所有六个人都被指控把本应支付给国际足联的大约4500万英镑骗了个精光。