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if... then...相关的网络例句

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If nevertheless we would attempt to define the notion "indefinite," then that's a paradox because if we succeed, then it is defined, which contradicts its meaning – its indefiniteness – and the word "indefinite" means that it cannot be defined.

但是如果我们试图界定概念"无限期",那么,这样的悖论,因为如果我们成功,那就定义这与它的意义--其不确定性和"无限期"的意思,所以无法确定。

Then the reconstructed data are analyzed by multiple statistical indexes such as T2 or SPE to determine if the supervised process exceeds the normal control limits. If fault occurs, then the supervising program will alarm to prompt that the process has abnormal states. Because it is hard to get the inverse mapping from the kernel space to the original space after the original data are nonlinear mapped by the KPCA method, hence it is difficult to diagnose how the fault happened.

该方法首先构造系统正常时的核主元模型,然后将新的数据映射到该核主元模型,对数据进行重构,重构的数据用多元统计指标T2或SPE判断监测过程是否超出了正常的控制限,若有故障发生,则监测程序将给于警告,提示过程出现了异常操作状况。

S1 is then changed to position 1. The voltage stored on C1 is inserted between the output and inverting input of the amplifier and the output of the amplifier changes by VIN to maintain the amplifier input at the input offset voltage. The output then changes from (VOS + IbiasR2) to (VIN + IbiasR2) as S1 is changed from position 2 to position 1. Amplifier bias current is supplied through R2 from the output of the amplifier or from C2 when S1 is in position 2 and position 1 respectively. R3 serves to reduce the offset at the amplifier output if the amplifier must have maximum linear range or if it is desired to DC couple the amplifier.

接着 S1 拨到位置 1,使 C1 的电压加在放大器的输出端和反相输入端之间,(由于电容端电压不能突变,所以)输出端的电压将产生大小等于 VIN 的变化,使放大器输入端维持输入失调电压,即当开关 S1 从位置 2 拨到位置 1 时,输出端电压将从(VOS + IbiasR2)变为(VIN + IbiasR2)。S1 处于位置 2 时,放大器的偏置电流是由输出端经电阻 R2 提供的,当 S1 转向位置 1 时则由 C2 提供。R3 的作用是降低输出失调电压,如果要求放大器具有最大的线性范围,或者采用直流耦合,就应该使用该电容。

For different polynomials g, if the characteristic polynomial of a n matrix A is irreducible, then we get some theorems to determine matrix equations g =A solvable; if it is reducible, then, to see n-dimension space vectors M over a field F as F-module, we use module theory to determine these equations solvable such that it is simpler and clearer to investigate these questions.

对于不同多项式g,当n阶矩阵A的特征多项式为不可约的,我们给出了矩阵方程g=A有解的判定定理;当A的特征多项式为可约的,把域F上的n维线性空间M作为由A导出的F -模,我们利用模论知识来决定矩阵方程g=A有解性,从而使这一问题变了简单,研究思路更加清晰。

No less, the hedging answer, I do not know, is incoherent. For if I know that I do not know, then I am a knower; and if I do not know that I do not know, then I should not answer.

至少,这含混的回答'我不知道'是不融贯的:因为如果我知道我不知道,那么我就是一个知道者;如果我不知道我不知道,那么我不应该回答。

If I answer,"Yes", then I would make them think that faith in God is very legalistic; if I answer "No" then they would think that being a Christian is just "talk" nothing needs to be changed.

如果我说"是"我会使人以为对神的信心是非常律法化;如果我答"不是",他们会想作为一个基督徒只是凭说话,不用在生活上有甚麼改变。

Professor刘纪鹏such as a joint letter to boost the stock market after yesterday刘纪鹏"Daily Economic News" said in an interview that "if the report can be sure, then we will launch for the size of the non-specific programs, called" zero-cost "program, if adopted by listed companies, then in December leveraging China's stock market is entirely possible."

10位教授,讨论股市20天出版的新书中建议利用火线10,如教授联名致信促进昨天刘纪鹏后,股市"每日经济新闻"刘纪鹏在接受采访时说:"如果报告可以肯定的,那么我们将推出的大小非特定程序,被称为"零成本"的计划,如果上市公司通过,然后在12月利用中国股市是完全可能的。"

Professor刘纪鹏such as a joint letter to boost the stock market after yesterday刘纪鹏"Daily Economic News" said in an interview that "if the report can be sure, then we will launch for the size of the non-specific programs, known as' zero cost 'program, if adopted by listed companies, then in December leveraging China's stock market is entirely possible."

"零成本"的解决办法的非股票的规模,充分利用火线出版的新书中建议10,如教授联名致信促进昨天刘纪鹏后,股市"每日经济新闻"刘纪鹏在接受采访时说:"如果报告可以肯定的,那么我们将推出的大小非特定程序,被称为'零成本'计划,如果上市公司通过,然后在12月利用中国股市是完全可能的。"

If the answer to both questions is yes, then companies are well advised to go into collective overdrive; if it is no, then they can experiment with more nuanced responses, such as lopping off a tainted product or sacrificing a rogue division.

如果两个问题的答案都为"是",那么,公司非常应该通过集体的努力来攻克危机;如果答案为"否",那么,公司可以尝试更细微的回应,比如砍掉一款声誉扫地的产品,或是牺牲掉一个有害全局的部门。

If the answer to both questions is yes, then companies are well advised to go into collective overdrive; if it is no, then they can experiment with more nuanced responses, such a lopping off a tainted product or sacrificing a rogue division.

如果两者的答案都是肯定的,那么这些公司就要全力以赴,克服危机。如果答案是否定的,那么他们可细微的调整对策,见机行事,如砍掉某个有影响力的商品,或牺牲这个八卦的部门。

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