查询词典 degree of a polynomial
- 与 degree of a polynomial 相关的网络例句 [注:此内容来源于网络,仅供参考]
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The number and stability of the limit cycles of a class of polynomial system with degree n are studied under some conditions by means of the results about Abel equation.
并利用关于Abel方程的这些结果得到了一类n次多项式系统在一定条件下极限环的个数和稳定性。
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Consequently, we get an estimate formula of the number n_1, bounded above by a polynomial of degree 24 in the parameters of F.
从而给出n_1的一个以F的参数的24次方为上界的估计式。
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Then we get an estimate formula of the number i\;bounded above by a polynomial of degree 9 in the parameters of F. As pointed by D.
从而给出n_1的一个以F的参数的9次方为上界的估计式。D。
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For the radical function where p(z is a polynomial of degree N with multi-branch points, this paper obtains a general method to get the function value on the given branch of analytic function.
对于具有多个有限支点的根式函数(其中p是任意的N次多项式),得到了求某个特定单值解析分支上的函数值的一般方法。
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In this paper, We firstly present a nonuniform sampling DCT method based on the relationship of Chebyshev polynomial interpolation and DCT, in which, the sampling points are chosen as zeros of Nth degree Chebyshev polynomials of the first kind.
文章首先利用Chebyshev多项式插值与DCT变换之间的相互关系,提出了基于第一类Chebyshev多项式的第N次多项式的零点作为非均匀取样点的DCT变换方法。
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A modified Euclidean algorithm was proposed by the generalization of synthetic division. It didn't judge the degree of polynomial and could decrease the complexity of decoding and hardware circuit and improve the decoding speed.
通过对综合除法进行推广,提出了一种改进型欧几里德算法,它不需要进行多项式次数的判断,能够降低译码的复杂度,减少硬件电路的复杂性,提高译码速度。
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We know that the solutions of quadratic, cubic and quartic can be expressed by radicals. As to the solution of the quintic which has became an issue for past two or three hundred years, it was not solved until 1832 a great young Mathematician of French named Galois who recommended group theory that proved a polynomial of degree 5 and over 5 can't be solvable by radicals.
中文摘要我们知道二次、三次及四次的方程式都可以用根式表示,至於五次方程式的解迟迟无法解决,这个问题持续了两三百年,直到1832年,一位法国青年Galois在其决斗前夕,在他的遗书中,这位伟大的青年数学家引进了群的理论,证明了:五次及五次以上的方程式,不可能有公式解。
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Theorem 2.4.2 Let F be a family of holomorphic functions in a domain D and k≥2 be a positive integer, K be a positive number and letα be a polynomial of degree p.
定理2.4.2设F为区域D内的一个全纯函数族,k (≥2)是一正整数,α是一次数为p≥1的多项式。
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Firstly, we prove a proposition : the leading coefficient regarded as a polynomial in q~n, q~(1/2 of the recurrence is not equal to zero for all n ≥ [m/2] + 1, where m is the degree in q~(1/2) of the leading coefficient.
首先,我们证明了一个命题:迭代关系的首项系数关于q~n,q~(1/2的多项式对所有的n≥1[m/2]+1均不为零,其中m为首项系数中q~(1/2)的次数。
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The resulting surface has a degree 4 parametric polynomial representation and is represented as a network of tangent plane continuous triangular Bézier patches.
生成的曲面有一个4次参数多项式表示并且被表示成一个切平面连续的三角形Bézier片网。
- 推荐网络例句
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I didn't watch TV last night, because it .
昨晚我没有看电视,因为电视机坏了。
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Since this year, in a lot of villages of Beijing, TV of elevator liquid crystal was removed.
今年以来,在北京的很多小区里,电梯液晶电视被撤了下来。
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I'm running my simile to an extreme.
我比喻得过头了。