查询词典 cosine circle

Mathematics: Understands and applies basic and advanced properties of the concepts of geometry; Use the Pythagorean theorem and its converse and properties of special right triangles to solve mathematical and real-world problems; Understands the basic concepts of right triangle trigonometry (e.g., basic trigonometric ratios such as sine, cosine, and tangent); Uses trigonometric ratio methods to solve mathematical and real-world problems (e.g., determination of the angle of depression between two markers on a contour map with different elevations); Uses properties of and relationships among figures to solve mathematical and real-world problems e.g., uses the property that the sum of the angles in a quadrilateral is equal to 360 degrees to square up the frame for a building; uses understanding of arc, chord, tangents, and properties of circles to determine the radius given a circular edge of a circle without the center

数学：理解和应用几何概念的初级和高级特性；用毕德哥拉斯定理、逆定理以及特殊直角三角形性质解决数学的和现实世界的问题；理解基本的直角三角形三角比；运用三角比方法解决数学的或现实的问题。（等高线图上的两个标记之间的俯角确定）运用形体之间的关系及其属性解决数学的或现实的问题（利用四边形内角和等于360度来为建筑物框架取正，运用弧，弦，切线和圆的性质确定缺少中心的一段圆弧的圆心

Results show that parabola is the most suitable one for the displacement-based method, following with cosine curve being the second and then circle the third,while hyperbola is unfit for the method.

认为抛物线最适合在位移法中使用，正弦曲线次之，圆曲线要有所限制，而双曲线则不宜采用。

Advantech PCI-1720 applications, applied to two channels of simultaneous output of sine and cosine curves to form a circle.

详细说明：研华PCI-1720应用程序，应用在两个通道同步输出正弦和余弦曲线，组成圆形。

Seasonal feature of occuring measles before and after immune planning was studied with proportion method of circle distribution and cosine model.

本文应用圆形分布构成比法与余弦模型对某地开展计划兔疫前后各12年麻疹发病季节特征进行分析。

Singer Leona Lewis and former Led Zeppelin guitarist Jimmy Page emerged as the bus transformed into a grass-covered carnival float, and the pair combined for a rendition of "Whole Lotta Love".

歌手leona刘易斯和前率领的飞艇的吉他手吉米页出现巴士转化为基层所涵盖的嘉年华花车，和一双合并为一移交&整个lotta爱&。

This is Kate, and that's Erin.

这是凯特，那个是爱朗。