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circle dot相关的网络例句

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与 circle dot 相关的网络例句 [注:此内容来源于网络,仅供参考]

This is a paper, there is a circle in it ,what can you imagine the circle?

这是一张纸,纸上有一个圆,你能把这个圆想象成什么?

There is a circle in it ,what can you imagine the circle?

这是一张纸,纸上有一个圆,你能把这个圆想象成什么?

He is well known in bussiness circle and has a large circle of friends .

他在商界是知名人士而且也有很多朋友。

Linear is infinitely large section of the circle, the point is infinitely small circle, the spiral is the synthesis and other factors.

直线是无限大的圆之一段,点即是无限小的圆,螺旋则是国与其它因素的合成。

Celtic Circle Tea Infuser - A Celtic circle made of lead-free pewter is attached ...

凯尔特圆茶infuser -凯尔特圈所作的铅免费锡金是重视。

Since representation of the subclass object starts out like the representation of a superclass object, the circle can always pretend to be a point — at the initial address of the circle's representation there really is a point's representation.

因为子类的表示开始于一个非常像其父类的结构,所以圆可以把自己伪装成一个点——圆的物理表示的地址的前面部分就是一个点的表示。

Constraint equations are derived to improve the original circle detection algorithm, which based on right triangles inscribed in a circle.

建立了条件约束方程组对基于圆内接直角三角形的圆检测算法加以改进。

Realized the arbitrary triangle inscribed circle, the circle of the formula.

详细说明:实现了任意三角形内切圆、外接圆的计算公式。

A fast and accurate arithmetic method by the judgement standard of using the maximum inscribed circle for evaluating the errors ofroundness is introduced, and a program to evaluate of the errors of the circle roundness is designed in this paper.

介绍了利用最大内接圆判别准则快速精确求解圆度误差的基本思想,设计了用最小外接圆法评定圆度误差的程序设计技术。

The class one which was expressed by diameters of pore maximum inscribed circle was adapted and a new distribution model expressed by diameters of pore area equivalent circle modified with fiber thickness was presented.

以几何概率和平面随机分割理论为依据,分析了非织造布中孔隙结构的分布模型,将经典的以内按圆直径表示的有效孔径分布模型改为以面积等效圆直径表示的有效孔径分布模型,并结合纤维细度进行修正,实验证明,该模型更符合实际情况。

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推荐网络例句

He paid $5,000 for this cupcake.

他我这个纸杯蛋糕花了5000美元。

I mean, if you want to, that is

我的意思是,如果你们想吃的话。

In addition to his fee, he would be awarded an unaltered clone of himself.

除了费用,他将获得一个不作任何改造的克隆体。