查询词典 available byte

In "Big Endian" form, by having the high-order byte come first, you can always test whether the number is positive or negative by looking at the byte at offset zero.

在"大终结着"的形式中，靠首先提取高位字节，你总是可以由看看在偏移位置为0的字节来确定这个数字是正数还是负数。

The device is byte controlled with each byte func- tioning identically, but independent of the other.

该设备是字节的每个字节化Func - tioning相同的控制，但其他独立。

To find these memory mapped expansion ROMs during boot, PC BIOS implementations scan real memory from 0xC0000 to 0xF0000 on 2 kilobyte boundaries looking for a 0x55 0xaa signature, which is immediately followed by a byte indicating the number of 512 byte blocks the expansion ROM occupies in real memory.

为了在开机时找到这些记忆体映射的扩充唯读记忆体，PC BIOS 会扫描实体记忆体，从 0xC0000 到 0xF0000 的 2KB 边界中寻找 0x55 0xaa 记号，接在其后的是一个位元，表示有多少个扩充唯读记忆体的 512 位元区块占据真实记忆体空间。

For example, if a keyboard is interrupted while sending the second byte of a two-byte break code, it will need to retransmit both bytes of that break code, not just the one that was interrupted.

举个例子，如果当发送一个两字节断码的第2个字节时，键盘被中断，它将需要重新发送此断码的两个字节，而不仅仅时被中断掉的那个字节。

High byte is scan code, low byte is ASCII code.

高字节是扫描码，低字节是 ASCII 码。

The high byte is the scan code and the low byte is ASCII code.

高字节是扫描码，低字节是 ASCII 码。

The firmware of the AT90S2313 (or ATtiny2313) its very complicated because, we have to convert the 'septets' of the phone to 'octets' because the AVR need bytes with 8 bits length ( The 'septet' is 1 byte with 7 bits length and 'octet' is 1 byte with 8 bits length).

AT90S2313 (或ATtiny2313的)固件比较复杂，因为，我们必须转换移动电话'7-bits编码'成AVR需要的8位长度字节的'8-bit编码'('7-bits编码'是7位长度的一个字节，'8-bits编码' 是8位长度的一个字节)。

If you need 100% certainty, SpaceMan 99 can do a full byte by byte comparison between files.

如果您需要百分之一百的肯定，货架99可以做充分字节由字节的对比文件。

UTF-8 is a superset of ASCII; the byte range 0 to 127 in UTF-8 exactly matches the ASCII mapping,and all ASCII characters 0 to 127 are represented by just one byte.

UTF-8编码是ASCII的一个超集，在0-127之间的字符排列顺序是按照ASCII中的顺序来进行排列的。

Decrypts a byte array and returns the result in a new byte array which must be deallocated by the caller.

解密的字节数组，并返回一个新的字节数组必须由调用者释放的结果。

But this is impossible, as long as it is engaging in a market economy, there are risks in any operation.

但是，这是不可能的，只要是搞市场经济，是有风险的任何行动。

We're on the same wavelength.

我们是同道中人。