查询词典 arithmetic progression
- 与 arithmetic progression 相关的网络例句 [注:此内容来源于网络,仅供参考]
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Geometric progression - Geometric series ; arithmetic series - arithmetic-level ...
几何级数——等比级数;算术级数——等差级。。。
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"Zhang Jian Qiu count as" Communication is the question 92, the achievements of the more prominent and there is the common denominator least common multiple of the calculation, the arithmetic progression of the problem to solve, some uncertainties, such as problem solving equation.
张丘建算经》现传本有92问,比较突出的成就有最大公约数与最小公倍数的计算,各种等差数列问题的解决、某些不定方程问题求解等。
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Rather than alwaysiterating over an arithmetic progression of numbers,or giving the user the ability to define both the iteration step andhalting condition, pythonsfor statement iterates over the items of anysequence, in the order that they appear inthe sequence.
通常的循环可能会依据一个等差数值步进过程或由用户来定义迭代步骤和中止条件,python 的 for 语句依据任意序列中的子项,按它们在序列中的顺序来进行迭代。
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Thus the above results imply the well known Linnik Theorem[21]on the leastprime in an arithmetic progression,and our result(2)implies 〓,(3)implies
因而上述问题均蕴含了Linnik关于算术级数中最小素数的著名定理。作为直接推论(2)和(3)分别蕴含了Linnik常数≤34和≤128/9。
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The dynamic process of the aero engine was described by using the Volterra progression model. And identification arithmetic of the Volterra progression model for aero engines was proposed. It was applied to a certain turbofan engine by imitating the dynamic respondence.
利用Volterra级数对航空发动机的动态过程进行描述,建立非线性模型,提出了模型的辨识算法利用某型涡扇发动机的动态仿真,进行了发动机Volterra模型辨识及验证。
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Around AD 1000, the Islamic mathematician , Ibn al-Haytham, was the first to derive the formula for the sum of the fourth powers of an arithmetic progression , using a method that is readily generalizable to finding the formula for the sum of any higher integral powers, which he used to perform an integration.
公元1000年,伊斯兰数学家,伊本Haytham ,是第一个公式推导的总和第四权力算术级数,使用方法很容易推广找到公式的总和任何高积分的权力,他用来执行一体化。
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For interpreted preceding N terms of inner product of arithmetic progression with 2-order symmetric sequence with property of sequence the expression is be made up of the same like with generalized diagram multiplication method symmetric formula.
利用对称数列性质分析等差数列与二阶对称数列的内积,建立与广义图乘法对称型公式一致的数列内积的对称型公式。用算例说明公式在求弯矩、数列和概率中的应用
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Generally, The gauge reading demarcated in the laboratory is increasing arithmetic progression,so we can use null method that we intercalate sequential numbers in order to calculate simply. The sum of these sequential numbers are zero. We must intercalate different sequential numbers while the number of trials is odd or even.
因为在试验室标定时,压力表读数一般是按照等差数列递增的,所以为了计算的简便,可用"零点法"设置等差序号,使这一列数据的总和为零,此时要注意当试验次数分别为偶数和奇数时不同地设置等差序号的方法。
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By reducing positions when they were losing money, the Turtles countered the arithmetic progression toward "ruin" effectively.
亏损时减仓,海龟们计算连续亏损的过程。
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This essay deduces the power sum formula of an arbitrary arithmetic progression step by step on the basis of Euler-Maclaurin formula,and then achieres the compute formula of natural number power sum -∑ni=1i m.
前n个自然数的方幂和,∑ni=1im是一个古老的难题。
- 推荐网络例句
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We have no common name for a mime of Sophron or Xenarchus and a Socratic Conversation; and we should still be without one even if the imitation in the two instances were in trimeters or elegiacs or some other kind of verse--though it is the way with people to tack on 'poet' to the name of a metre, and talk of elegiac-poets and epic-poets, thinking that they call them poets not by reason of the imitative nature of their work, but indiscriminately by reason of the metre they write in.
索夫农 、森那库斯和苏格拉底式的对话采用的模仿没有一个公共的名称;三音步诗、挽歌体或其他类型的诗的模仿也没有——人们把&诗人&这一名词和格律名称结合到一起,称之为挽歌体诗人或者史诗诗人,他们被称为诗人,似乎只是因为遵守格律写作,而非他们作品的模仿本质。
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The relationship between communicative competence and grammar teaching should be that of the ends and the means.
交际能力和语法的关系应该是目标与途径的关系。
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This is not paper type of business,it's people business,with such huge money involved.
这不是纸上谈兵式的交易,这是人与人的业务,而且涉及金额巨大。