查询词典 algorithm of euclid

The algorithm is based on a modification of Euclid s algorithm.

在扩展欧几里得算法的基础上提出了有限域乘法逆元的计算方法。

A well-known example of an algorithm is Euclid's algorithm, which is a process for calculating the greatest common divisor of two integers m and n.

在运算法则中一个著名的例子就是计算两个整数m和n的最大公约数的欧几里德运算法则。

The accuracy of the algorithm is constantly the iso-distance, 1/2, which is not as bood as that of the best approximation methods.

本文最后研究了该方法在栅格圆环、圆盘及球面、球等生成及Euclid距离变换中的应用。

This algorithm is proposed on the basis of the thought as follovvs: as for three dimensional Euclid space, the feasible region of any linear programming problem is a extended convex polyhedron, of which surface is consisted of some planes, and its objective function can be regarded as a parallel plane pencil with objective function value acting as parameter.

如果线性规划问题有最优解，那么过可行域的一已知顶点必至少存在这样一条棱——它以该己知顶点为一端点，可行域的另一顶点为另一端点，并使目标函数在另一端点的函数值优于己知端点的函数值，否则，该己知点就是线性规划问题的最优解。

Firstly, Dempster-Shafer is developed by not only considering the certainty of the evidence, but also considering the average support of the evidence to different subsets in the assignment framework so that it can give more reliable combination result. Secondly, amplitude ratio feature and Euclid distance of the probability density distribution function in Pearson graph from different temporal SAR images are extracted to present change feathers in different scales. Finally, the improved Dempster-Shafer algorithm is applied to fuse the two different features to detect change information of SAR images.

首先通过综合考虑证据本身的确信度和证据对辨别框架中子集的平均支持度进行证据间的加权合成，改进证据理论对证据的合成，提高其可靠性；然后提取不同时相图像间的散射幅度的对比度和概率密度分布函数在皮尔逊图中的欧式距离，两种特征参数代表了像元级和区域级不同空间尺度下微波遥感图像中关于地表变化的信息；最后将改进的证据理论用于两特征之间的融合处理，得到地表的变化信息。

Singer Leona Lewis and former Led Zeppelin guitarist Jimmy Page emerged as the bus transformed into a grass-covered carnival float, and the pair combined for a rendition of "Whole Lotta Love".

歌手leona刘易斯和前率领的飞艇的吉他手吉米页出现巴士转化为基层所涵盖的嘉年华花车，和一双合并为一移交&整个lotta爱&。

This is Kate, and that's Erin.

这是凯特，那个是爱朗。