查询词典 Riemann

We construct an explicit finite difference approximation for the equation by using the equivalence relation between Riemann-Liouville fractional derivative and Grünwald-Letnikovmake fractional derivative.

再利用Riemann-Liouville分数阶导数与Grtinwald-Letnikov分数阶导数之间的等价关系，构造一显式有限差分近似，这一离散格式可以解释为一个随机游走模型，并且收敛于稳定的概率分布。

In the first chapter,the Riemann-Hilbert boundary value problem of non-normal type for biregularfunctions and some boundary value problems of the inhomogeneous secondorder equation

共有三章，在第一章中主要运用文[2]中的理论与方法讨论了平面上双解析函数的非正则型Riemann-Hilbert边值问题及非齐次二阶方程

Gauss assigned to Riemann the subject of the foundations of geometry as the one on which he should deliver his qualifying lecture.

Gauss 给 Riemann 指定把几何基础作为他应该发表的就职演说的题目。

Then we give the linear expression of,by f,g.h:=-f;=ρ·g,here ρ is the Gauss curvature of the Riemann manifold,wealso give the geomety explaination and geometrical pattern of these expressions.

给出了与对于f，g，h线性分解的形式。＝-f；＝-ρg，这里ρ是曲面的高斯曲率。并给出了各自几何意义的解释与图示。

"A geometer like Riemann might almost have foreseen the more important features of the actual world.

"，"一个像黎曼这样的几何学者几乎可以预见到现实世界的更重要的特徵。

A geometer like Riemann might almost have foreseen the more important features of the actual world.

一个像黎曼这样的几何学者几乎可以预见到现实世界的更重要的特征。

Mathematician successfully taken the first step for our country, he is the 20th century the great geometer, especially in the Gauss, Riemann, cards and pioneers as the successor.

数学家为我国踏出成功的第一步，他是20 世纪的伟大几何学家，尢在高斯，黎曼，卡当的继承者和开拓者。

Nonlinear Riemann boundary value problems and nonlinear Hilbert boundary value problems will be studied in this paper, because they have been researched seldom.

对于非线性的Riemann边值问题和非线性的Hilbert边值问题研究很少，本文试图在这些方面做一些工作。

Key words: applied mathematics; hyperbolicity; hyperbolic conservation laws; multi-class traffic flow Lighthill-Whitham-Richards model; Riemann invariants

引用格 式：杨建伟，王可，王红利。多等级交通流LWR模型的双曲性和Riemann不变量。中国科技论文在线精品论文，2009，2(1)：25～32。

The zeta function of Euler and Riemann, expressed as an infinite series and a curious product over all primes.

该zeta函数的欧拉和黎曼，表达了作为一个无穷级数和好奇的产品超过所有素数。

"Please accept this talisman as a token of our thanks."

请收下这个护身符以表达我们的感谢。

If I have that magic, I will be more acceptable in the society.

如果我拥有那种魔法，我将更加被这个社会所容纳。