查询词典 Q-factor
- 与 Q-factor 相关的网络例句 [注:此内容来源于网络,仅供参考]
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Mr. Watanabe of small Q back to the home, Watanabe emotional day for small Q deepen differences, but did not last long, as a young man of serious physical advances, Mr. Watanabe fell ill, and at this time only a return to good old small-Q training camp, the living here for three years.
渡边先生把小Q带回了家里,渡边对小Q的感情日异加深,可是好景不长,由于年轻时体力的严重透支,渡边先生病倒了,此时的小Q只有回到往日的训练营,这一住就是三年。
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While the standard Airy function, used frequently in the uniform asymptotic formulas for classical orthogonal polynomials, behaves like the exponential function on one side and the trigonometric functions on the other side of an extreme zero,the q-Airy polynomial behaves like the q-Airy function on one side and the q-Theta function on the other side.
在经典正交多项式的一致渐近公式中我们通常要用到Airy函数,这个Airy函数在一个极端零点的一边表现为指数函数,另一边又表现为三角函数。同样地,q-Airy多项式在一边表现为q-Airy函数,另一边又表现为q-Theta函数。
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According to the principle of A-O interaction and quartz′s different characteristic in the direction of parallel and perpendicular acoustics field, with a quarter-wave plate being inserted in an AO Q-switch Nd∶YAG laser cavity between mirror and Q-switch, AO Q-switch′s Bragg diffraction efficiency formula is put out theoretically. Consequently, the conclusion has been drawn by calculating simulation that the ability of a single AO Q-switch′s switching CW Nd∶YAG laser is increased.
结合声光相互作用理论和声光介质熔石英在平行和垂直于声场的两个方向具有不同声光优值的特性,理论推导了腔内引入四分之一波片后声光Q开关的布喇格衍射效率公式,计算模拟得出引入四分之一波片能够有效地提高声光Q开关关断连续Nd∶YAG激光的能力。
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If a subject who knows only P cannot deduce that Q (as the knowledge argument suggests), or if one can rationally conceive of P without Q (as the conceivability argument suggests), then it seems that P does not imply Q.
如果一个主体仅仅知道P,不能推理得到Q,或如果一个人可合理设想没有Q的P,那么似乎P并不蕴涵Q。
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This research uses the hydraulic model as an experimental tool. In different slopes (S=1/8、S=1/10), flow rates (Q=0.016cms、Q=0.032cms、Q=0.048cms), and the angles (θ=30°、θ=45°、θ=60°) of blocking pieces in the modified boat-passage fishway, the velocity and depth were measured.
本研究以水工模型作试验,藉由改变改良型舟通式鱼道之阻流材角度(θ=30°、θ=45°、θ=60°),在不同坡度(S=1/8、S=1/10)与流量(Q=0.016cms、Q=0.032cms、Q=0.048cms)下,量测流速及水深以观测水理变化。
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For example,the graph in Fig.3-5 is Hamiltonian(a possible path being P→Q→R→S→T→P)but is not quite Eulerian,since any path which includes every dege exactly once(e. g.P→Q→T→P→S→R→Q→S→T)must end up at a vertex different from the initial vertex.
例如,图3-5所示是一个哈密尔顿图(存在一条路P→Q→R→S→T→P)但不是一个欧拉图,这是因为图中任何包含所有边一次且仅一次的路(如P→Q→T→P→ S→R→Q→S→T)都不能回到原出发顶点。
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By using this method we obtain two gen-eralized transformation formulae of q-integral form,two identities of basic hypergeometric series,as well as formal extensions for q-Pfaff-Saalschütz formula,q-Chu-Vandermonde identity and a three-term transformation formula of _3φ_2-series.
我们推广了两个q-积分形式的变换公式和两个有关基本超几何级数的恒等式,还得到q-Pfaff-Saalschütz公式、q-Chu-Vandermonde恒等式和基本超几何级数中一个有关_3φ_(2~-)级数的三项变换公式等的形式推广。
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Firstly, we prove a proposition : the leading coefficient regarded as a polynomial in q~n, q~(1/2 of the recurrence is not equal to zero for all n ≥ [m/2] + 1, where m is the degree in q~(1/2) of the leading coefficient.
首先,我们证明了一个命题:迭代关系的首项系数关于q~n,q~(1/2的多项式对所有的n≥1[m/2]+1均不为零,其中m为首项系数中q~(1/2)的次数。
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For the coordination of multiple agents in noncooperation environment, we considered the learning aim as finding a Nash equilibrium strategy through in learning function taking other agent's actions into account. Therefore, we expended the single agent Q-learning algorithm into multiagent Q-learning algorithm. In addition, we proved the convergence of multi-agent Q-learning algorithm under certain general sum stochastic game architecture for only one Nash equilibrium or multiple same Nash equilibrium.
对于非合作环境下的多智能体协调我们通过在学习函数中考虑了智能体的联合行动,提出把学习目标作为求取一个Nash平衡点策略,这样将单智能体Q-learning算法扩展到多智能体的Q-learning算法;证明了在一定的一般和随机对策结构下具有一个或多个相同Nash平衡点条件下多智能体Q-learning算法的收敛性。
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It is shown that if L is a subalgebra of a Lie color algebra Q, then Q is an algebra of quotients of L if and only if Q is ideally absorbed into L.
利用没有非零零化子的理想对Lie color代数的商代数进行刻画,证明了:若L为Lie color代数Q的子代数,则Q为L的商代数当且仅当Q理想吸收于L。
- 相关中文对照歌词
- Q & A
- My I.Q.
- Payback (P's And Q's)
- Siq With A Q
- Q-Ball
- Bar-B-Q Pope
- Happened On A Saturday Night (Susie Q)
- Q
- Suzie Q
- Illusions (Q-Tip Remix)
- 推荐网络例句
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The labia have now been sutured together almost completely.The drains and the Foley catheter come out at the top.
此刻阴唇已经几乎完全的缝在一起了,排除多余淤血体液的管子和Foley导管从顶端冒出来。
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To get the business done, I suggest we split the difference in price.
为了做成这笔生意,我建议我们在价格上大家各让一半。
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After an hour and no pup, look for continued contractions and arching of the back with no pup as a sign of trouble.
一个小时后,并没有任何的PUP ,寻找继续收缩和拱的背面没有任何的PUP作为一个注册的麻烦。