查询词典 N-phenylaniline

The pupose of the research is to develops public key encryption and digital signature shemes based on matrix canonical decomposition problem, or matrix diagonalization problem over Z/n, the ring of integers with modulo-n addition and multiplication in particular, where n is an RSA modulus.

本课题研究基于矩阵经典分解问题，特别是Z/n上矩阵对角化问题的公钥密码与数字签名算法，其中n是一个RSA模数。新算法采用由一个矩阵多项式构成的多维单向陷门函数，其单向性由矩阵对角分解问题(即通过相似变换将矩阵化为对角型的问题)的复杂性来保障，对该函数求逆的陷门由矩阵的特征值或特征向量提供。

It is observed that each of the N nodes of an undirected double loop network can be represented by its coordinates in Cartesian coordinate system as mod N.

在这部分，我们主要是利用无向双环网的N个节点中的每个点都可用平面坐标系中的坐标，采用mod N的方式表示，从而发现N个节点在坐标平面中周期性地出现。

Through the analysis of the second power Cartesian product of natural number set N——N×N and the thirdpower Cartesian product of natural number set N——N×N×N,obtains the conclusion that they all have the bijective relation to natural number set N,it means that the set N×N and the set N×N×N are all countably infinite.

通过对自然数集合N的二次笛卡尔积运算———N×N和三次笛卡尔积运算———N×N×N的详细分析，得出了它们与自然数集合N之间都存在双射关系结论，即集合N×N和集合N×N×N都是可数无穷的。

Since any n x n doubly stochastic circulant matrix has a unique representation as a polynomial of degree n - 1 in the shift operator wn, the classification problem of primes in the doubly stochastic circulant matrices can be reduced to the solution of an equation over a doubly stochastic circulant matrix.

由于任一n阶双随机循环矩阵都可以唯一地表示为移位的n-1次一元多项式，从而可把双随机循环矩阵中素元的分类问题简化为解双随机循环矩阵上的一个方程。

According to Sarkovskii's theorem, if the continuous self-map f of the closed interval has a 3-periodic orbit, then f must has an n-periodic orbit for any positive integer n But f can not has all n-periodic orbits for some n.

但f不可能有所有类型的n-周期轨。例如：则f仅有两种类型的3-周期轨中的一类。这表明Sarkovskii定理远远没有给出周期轨之间的关系的全部信息。

If a n-dimensional unoriented cobordism class α_n containing a representative that admits a (Z_2)~k-action with fixed point set of constant codimension r,we may say that α∈is an ideal of the unoricnted cobordism ring MO_*=.

若n维未定向协边类α_n的一个代表元M~n上有不动点集为常余维数r的(Z_2)~k光滑作用，则记α_n∈J_~r.J_~=∑_n≥r_J_(n，k~r是未定向上协边环MO_+=∑_(n≥0)MO_n的理想。

This article presented a new fast algorithm of Moore-Penrose inverse for an m×n symmetric Loewner-type matrix with full column rank by forming a special block matrix and studied its inverse. Its computation complexity was O+O(n^2), but it was O(mn^2)+O(n^3) by using L(superscript +)=L(superscript TL^(-1)L.

论文通过构造特殊分块矩阵并研究其逆矩阵，给出了秩为n的m×n对称Loewner矩阵Moore-Penrose逆的快速算法，该算法的计算复杂度为O+O(n^2)，而通过L=L(上标 TL^(-1)L计算的复杂度为O(mn^2)+O(n^3)。

Rader's algorithm, exploiting the existence of a generator for the multiplicative group modulo prime N, expresses a DFT of prime size n as a cyclic convolution of size N 1, which can then be computed by a pair of ordinary FFTs via the convolution theorem (although Winograd uses other convolution methods).

Rader演算法提出了利用点数为N的DFT进行长度为N-1的回旋摺积来表示原本的DFT，如此就可利用摺积用一对基本的FFT来计算DFT。

This paper studies the curvilinear integral ∮ L[xn-1yn-1]/[x2n+k2y2n]where L is a sectioned smooth and no multiple points closed curve, n is some natural number, k is some positive number.

本文研究曲线积分x~(n-1y~(n-1)/x~(2n+k~2y~(2n)，其中L是公段光滑无重点的闭曲线，n为某一自然数，k为某一正数。首先利用极坐标变换将曲线积分化简，然后对n、L不同情况给出相应结果

Methods Fifty pairs of fresh colorectal cancer and homologous normal tissues were genotyped with Identifiler Kit and the mutations generated in cancer tissues were determined. The mutation rates, the numbers of locus matched without identical allele (A0), 1 identical allele (A1), or 2 identical alleles (A2) and the number of total identical alleles IA(subscript n were calculated. Frequency distributions of A0, A1, A2 and IA were compared among CR-N group, unrelated individual pairs and full sibling pairs. Discrimination functions were established for individual identification from tumor tissues with discriminatory analysis.

用Identifiler系统对50对新鲜结直肠癌组织及其身源正常组织组进行STR分型，计算CR-N组中变异STR基因座及全不同基因座数(A0)、半相同基因座数(A1)、全相同基因座数(A2)和共有等位基因数IA(下标 n，比较CR-N组、无关个体对组和全同胞对组中上述参数的分布差异，通过判别分析建立判别函数。

With Death guitarist Schuldiner adopting vocal duties, the band made a major impact on the scene.

随着死亡的吉他手Schuldiner接受主唱的职务，乐队在现实中树立了重要的影响。

But he could still end up breakfasting on Swiss-government issue muesli because all six are accused of nicking around 45 million pounds they should have paid to FIFA.

不过他最后仍有可能沦为瑞士政府&议事餐桌&上的一道早餐，因为这所有六个人都被指控把本应支付给国际足联的大约4500万英镑骗了个精光。