X'd

X'd的基本解释

-

[变形] x的过去分词

n.

字母x, 未知数

adj.

X形的, X级的(电影等), 第二十四的

与X'd相关的网络例句 [注：此内容来源于网络，仅供参考]

In Chapter 2, the D-symmetric solutions of matrix equation A~TXA = B on the linear manifold S ={X ∈ D~(-2)SR~|XZ = Y, Y = Y{D~2Z+D~2Z, Z~TD~2Y = Y~TD~2Z, Y,Z∈ R~}, by applying the generalized singular value decomposition of a matrix pair, the necessary and sufficient conditions for the existence and the expressions for the D-symmetric solutions of matrix equation A~TXA — B on the linear manifold are established.

运用矩阵对的广义奇异值分解，给出了这类线性流形上矩阵方程A~TXA=B存在D对称解的充要条件及其通解的表达式。另外给出了它的D对称最小二乘解的表达式。

This is achieved by prefacing the member number with S, X, D or Z respectively.

这是通过与S作序的，十，分别为D或成员数目。

Tz = 2Gk q 即 z = 2Gk q /T 40 Suppose the volume between membrane and the boundary plane is V, and we notice that 2 ∫∫ d x d y = M Then we have Thereby we have q qM V =∫∫ zdxdy =∫∫ dxdy = 2GTk 4GTk M 2 Gk = 2V q /T From τ zx =τ xz =, y z 2Gk τ zx /= y q / T τ z y =τ yz = x 41 Moreover, we get 设薄膜及其边界平面之间的体积为V,并注意到 2 ∫∫ d x d y = M 则有从而有由又可得 q qM V =∫∫ zdxdy =∫∫ dxdy = 2GTk 4GTk M 2 Gk = 2V q /T τ zx =τ xz =, y z 2Gk τ zx /= y q / T τ z y =τ yz = x 42 Adjust the pressure q of which the membrane is under, and make the rights of formulas,, equal to one, then we can gain some conclusions as follows:(1) The stress function of wringed pole equals to the uprightness angle of the membrane (2) The torsion M which wringed pole received equals to two times of the volume between the membrane and the boundary plane.

o b y a x 43 调整薄膜所受的压力q，使得，，三式等号的右边为1，则可得出如下结论：(1)扭杆的应力函数等于薄膜的垂度z。(2)扭杆所受的扭矩M等于该薄膜及其边界平面之间的体积的两倍。

与X'd相关的网络解释 [注：此内容来源于网络，仅供参考]

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